Capacitance of Parallel Plate Capacitor
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A simple pendulum of period T has a metal bob which is negatively charged. If it is allowed to oscillate above a large positively charged metallic plate, its period of oscillation will be,
Increases
Remains the same
May increase or decrease
Decreases
- (cosαcosβ)2
- (cosβcosα)2
- (sinαsinβ)2
- (sinβsinα)2
Where is the electric field uniform?
- 12ε0E2Ad
- ε0AEd
- E2Adε0
- 12ε0E2
Two parallel plate capacitors of capcitances C and 2C are connected in parallel and changed to a potential V by a battery. The battery is then disconnected and the apsce between the plates of capacitor C is completely filled with a material of dielectric constant K. The potential difference across the capacitors now becomes
VK+1
2VK+2
3VK+2
3VK+3
What is the dimensional formula of capacity?
The introduction of a metal plate between the plates of a parallel plate capacitor increases its capacitance by 4.5 times. If d is the separation of the two plates of the capacitor, the thickness of the metal plate introduced is
d3
5d9
7d9
d
- 9nF
- 90nF
- 900nF
- 0.9 nF
(Dielectric strength of air : 3×106Vm−1)
- 1000V
- 2000V
- 3000V
- None of these
- Equivalent capacitance of system is 2ϵoAd
- Energy stored between plates 1 and 2 is ϵoAE22d
- Energy stored between plates 3 and 4 is zero
- Equivalent capacitance of system is 5ϵoA4d