Gauss's Law
Trending Questions
- 4πϵ0b2(b−a)
- 4πϵ0b
- 4πϵ0ab(b−a)
- 4πϵ0a
- 4πϵ0b
- 4πϵ0ab(b−a)
- 4πϵ0a
- 4πϵ0b2(b−a)
- U0n7/6
- UOn5/3
- U=U0n5/6
- UOn5/6
The electric flux for Gaussian surface A that enclose the charged particles in free space is (given q1=−14 nC, q2=78.85 nC, q3=−56 nC)
- 103 Nm2 c−1
- 103 CN−1 m−2
- 6.32×103 Nm2 C−1
- 6.32×103 CN−1 m−2
[MP PMT 1994, 95; DCE 1999, 2001; AIIMS 2001]
The figure shows an imaginary cube of length L/2 and a uniformly charged rod of length L touching the centre of the right face of the cube normally. At time t=0, the rod starts moving to the left slowly at a constant speed 'v'. the electric flux(F) through the cube is plotted against time(t). the correct graph showing the variation of flux with time is
- Q3ε0cosα
- q2ε0sinα
- q2ε0(1−cosα)
- q2ε0(1−sinα)
- 8eϵ0
- 16eϵ0
- eϵ0
- zero
- Q3ε0cosα
- q2ε0sinα
- q2ε0(1−cosα)
- q2ε0(1−sinα)
- 0
- Q4ε0
- Q24ε0
- Q8ε0
- False
- True
The electric flux through the surface S as due to all the charges as shown in following figure isq1+q3−q2−q4ϵ0
True
false
- Q3ε0
- Q4ε0
- Q5ε0
- Q6ε0
- 4×103 C
- −4×103 C
- (4×103)ϵC
- −4×103ϵ0 C
An electric dipole is an arrangement of two equal charges of equal magnitude but opposite nature, separated by some fixed distance.
Now consider a dipole enclosed inside a closed surface S. The flux through the surface S is zero.
True
false
Gauss law for magnetic field fetches a flux identically equal to zero because
Magnetic field obeys the superposition principle
Magnetic field changes with changing electric field
Magnetic monopoles can't exist theoretically
Magnetic monopoles have not been seen to exist
Comment on the correctness of the following two statements:
Statement I => Gauss’s law is valid only for symmetrical Gaussian surfaces with respect to the charge distribution.
Statement II => Gauss’s law is valid only for charges placed in vacuum.
True, True
True, false
False, True
False, False
- ∮(→E1+→E2+→E3).d→A=q1+q2+q32ϵ0
- ∮(→E1+→E2+→E3).d→A=q1+q2+q3ϵ0
- ∮(→E1+→E2+→E3).d→A=q1+q2+q3+q4ϵ0
- None of the above
- Electric potential at the centre of a uniformly charged spherical shell due to its own charge is zero.
- Electric potential at the centre of a uniformly charged sphere due to its own charge is zero.
- Self energy of a dipole is positive.
- If we change the reference point, the potential difference between 2 points will not change.
A charge q is located above the centre of a square plate of side a, at a distance a2. The flux of electric field through the plate Is?
qϵ0
q2ϵ0
q4ϵ0
q6ϵ0
- 12ϵ0
- 24ϵ0
- −6ϵ0
- 8ϵ0
A spherical volume contains a uniformly distributed charge of volume density 2.0×10−4 Cm−3. Find the strength of electric field at a point inside the volume at a distance 4.0 cm from the centre.
3×104 NC
3×105 NC
3×106 NC
3×107 NC
Comment on the correctness of the following two statements based on the given situation.
Consider a line of length ‘l’ and uniform charge density λ. Assume a Gaussian surface S, a cylinder of radius R and height h.
Statement 1: φ=flux through S=λHϵ0
Statement 2: |→E|at all the points on its curved surface=λϵ02πR
True, True
True, false
False, True
False, False
- Qϵ0
- 100Qϵ0
- 10Q(πϵ0)
- 100Q(πϵ0)
Electric charges are distributed in a small volume. The flux of the electric field through a spherical surface of radius 10 cm containing the total charge is 25 V-m. The flux through a concentric sphere of radius 20 cm will be?
25 V-m
50 V-m
100 V-m
200 V-m