Image Formation in Concave Mirror
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An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror with a radius of curvature of 30 cm. Find the position of the image, its nature, and size.
The image formed by a concave mirror is observed to be virtual, erect, and larger than the object. Where should be the position of the object?
Between the principal focus and the center of curvature
At the center of curvature
Beyond the center of curvature
Between the pole of the mirror and its principal focus.
- d=2f, 4f
- d=2f, 3f
- d=3f, 4f
- d=2f
- False
- True
- 40 cm, 20 cm
- 30 cm, 50 cm
- 60 cm, 80 cm
- 25 cm, 15 cm
An object is placed at a distance of from a convex mirror of a focal length of . Find the position and nature of the image.
Draw the ray diagrams for the following positions of an object in front of a concave mirror.
Between centre of curvature and focus.
The graph shows variation of v with change in u for a mirror. Points plotted above the point P on the curve are for values of v [CPMT 1987]
- Smaller then f
Smaller then 2f
Larger then 2f
Larger than f
- 22.5 cm
- 7.5 cm
- 30 cm
- 45 cm
- P & Q
- Q & R
- R & P
- P, Q & R
A thin rod of length f/3 lies along the axis of a concave mirror of focal length f One end of its magnified image touches an end of the rod. The length of the image is
[MP PET 1995]
- f
- 12f
- 2f
- 14f
- f
- 2f
- 4f
- Zero
- 3 cm
- 2 cm
- 1 cm
- 0 cm
- 0.4cm away from the mirror
- 0.4cm towards the mirror
- 0.8cm away from the mirror
- 0.8cm towards the mirror
- Infinity
- f
- f2
- 2f
- real, inverted and of same size
- real, inverted and smaller in size
- virtual, erect and larger in size
- virtual, erect and smaller in size
Which of the following graphs is the magnification of a real image against the distance from the focus of a concave mirror
- u=+25 cm
- u=−30 cm
- u=−25 cm
- u=−50 cm
- 20 cm
- 15 cm
- 40 cm
- 35 cm
- (−407 cm, −17 cm)
- (+407 cm, +17 cm)
- (−207 cm, −17 cm)
- (+207 cm, +17 cm)
- 10 cm
- 15 cm
- 2.5 cm
- 5 cm
A concave mirror of focal length 100 cm is used to obtain the image of the
sun which subtends an angle of 300 The diameter of the image of the sun
will be
1.74 cm
0.87 cm
0.435 cm
100 cm
- 0.4 cm away from the mirror
- 0.4 cm towards the mirror
- 0.8 away from the mirror
- 0.8 cm towards the mirror
- Always True
- Always False
- May be True in some cases
- Data Insufficient
- 3 cm
- 2 cm
- 1 cm
- 0 cm