Impedance in RLC Circuit
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Q. For series L−C−R, graph between peak current and frequency (ω) shown in the figure below.
The correct order for R1, R2 and R3
The correct order for R1, R2 and R3
- R1>R2>R3
- R2>R1>R3
- R3>R1>R2
- R3>R2>R1
Q. For a series LCR circuit, power factor at resonance is equal to -
- 0.9
- 0.5
- 0.7
- 1
Q. In the given circuit, peak voltage across the resistor and capacitor are 6V and 8V. At an instant when voltage across capacitor is 4V in magnitude,
- Voltage across resistance is −3√3 V
- Voltage across resistance is 3√3 V
- Peak source voltage is 5√3
- Current in circuit is ahead of source voltage
Q. Solve this:
Q. An inductor coil stores U energy when i current is passed through it and dissipates energy at the rate of P. The time constant of the circuit, when this coil is connected across a battery of zero internal resistance is
Q. An inductor coil stores U energy when i current is passed through it and dissipates energy at the rate of P. The time constant of the circuit, when this coil is connected across a battery of zero internal resistance is
Q. A resistor and an inductor are connected to an AC supply of 120 V and 50 Hz. The current in the circuit is 3 A. If the power consumed in the circuit is 108 W, then the resistance in the circuit is
- 12 Ω
- 40 Ω
- √(52×28) Ω
- 360 Ω
Q. In a series circuit R = 300 Ω , L = 0.9 H, C = 2.0 μF and ω = 1000 rad/sec. The impendence of the circuit is
- 1300 Ω
- 900 Ω
- 500 Ω
- 400 Ω
Q. An alternating voltage, of peak value 283 V and of varying frequency, is applied across a series LCR combination in which, R=3 Ω, L=25 mH and C=400 μF. The frequency of the source for which the current and voltage are in phase, is -
Q.
A lamp consumes of electrical energy in . What is its power?
Q. A series R-C combination is connected to an AC voltage of angular frequency ω=500 rad/s. If the impedance of the R-C circuit is R √1.25, the time constant of the circuit in milliseconds upto two digits after the decimal point is
.