Instantaneous acceleration
Trending Questions
Q. A boy stretches a stone against the rubber tape of a catapult or 'gulel' (a device used to detach mangoes from the tree by boys in Indian villages) through a distance of 24 cm before leaving it. The tape returns to its initial normal position, accelerating the stone over the stretched length. The stone leaves the gulel with a speed of 2.2 m/s. Assuming that acceleration is constant while the stone was being pushed by the tape, find the magnitude.
- 8.1 m/s2
- 9.1 m/s2
- 10.1 m/s2
- 11.1 m/s2
Q. In the one-dimensional motion of a particle, the relation between position x and time t is given by x2+2x=t , where x>0. Choose the correct statement.
- The retardation of the particle is 14(x+1)3.
- The velocity of the particle is 1(x+1)3.
- Both are correct
- Both are wrong
Q. The displacement of a particle varies with time t, x=ae−at+beβ t where a, b, α and β are positive constants. The velocity of the particle will
- Go on decreasing with time
- Be independent of α and β .
- Drop to zero when α=β
- Go on increasing with time
Q. A particle moves along x-axis and its acceleration at any time t is a=2sin(πt), where t is in seconds and a is in m/s2. The initial velocity of particle (at time t=0) is u=0. The distance travelled (in meters) by the particle from time t=0 to t=1 s will be
- 2π
- 1π
- 4π
- None of these
Q. The relation between time t and distance x is t=αx2+βx where α and β are constants. The retardation is
- 2 αv3
- 2 βv3
- 2 αβv3
- 2 β2v3
Q. A particle is moving along a straight-line path according to the relation
S2=at2+2bt+c
S represents the displacement covered in t seconds and a, b, c are constants. The acceleration of the particle varies as
S2=at2+2bt+c
S represents the displacement covered in t seconds and a, b, c are constants. The acceleration of the particle varies as
- S−3
- S3/2
- S−2/3
- S2
Q. A particle moves along a straight line. Its position at any instant is given by x=32t−8t33 where x is in m and t in s. The acceleration of the particle at the instant when particle is at rest will be
- −16 m/s2
- −32 m/s2
- 16 m/s2
- 32 m/s2
Q. The motion of a body is given by the equation dv(t)dt=6.0−3v(t). Where v(t) is speed in ms and t in sec. If body was at rest at t = 0
- The terminal speed is 3.0ms
- The speed varies with the time as v(t)=2(1−e−3t)ms
- The speed is 0.1ms when the acceleration is half the initial value
- The magnitude of the initial acceleration is 0.5ms2
Q. A boy stretches a stone against the rubber tape of a catapult or 'gulel' (a device used to detach mangoes from the tree by boys in Indian villages) through a distance of 24 cm before leaving it. The tape returns to its initial normal position, accelerating the stone over the stretched length. The stone leaves the gulel with a speed of 2.2 m/s. Assuming that acceleration is constant while the stone was being pushed by the tape, find the magnitude.
- 8.1 m/s2
- 9.1 m/s2
- 10.1 m/s2
- 11.1 m/s2
Q. When acceleration be function of velocity as a=f(v), then
- The displacement (x)=∫vdvf(v)
- The acceleration may be constant
- The slope of acceleration versus velocity graph may be constant.
- (a) and (c) are correct.
Q. The acceleration of a particle is increasing linearly with time t as bt . The particle starts from the origin with an initial velocity vo . The distance travelled by the particle in time t will be
- v0t+13bt2
- v0t+13bt3
- v0t+16bt3
- v0t+12bt2
Q. Given below are the equations of motion of four particles A, B, C and D.
xA=6t−3;
xB=4t2−2t+3;
xC=3t3−2t2+t−7;
xD=7cos60°−3sin30°
Which of these four particles move with uniform non-zero acceleration?
xA=6t−3;
xB=4t2−2t+3;
xC=3t3−2t2+t−7;
xD=7cos60°−3sin30°
Which of these four particles move with uniform non-zero acceleration?
- A
- B
- C
- D
Q. A particle is moving along positive x-axis and at t=0, the particle is at x=0. The acceleration of the particle is a function of time. The acceleration at any time t is given by a=2(1–[t]) where [t] is the greatest integer function . Assuming that the particle is at rest initially, the average speed of the particle for the interval t=0 s to t=4 s is
- 1 m/s
- 0.5 m/s
- 2 m/s
- 1.5 m/s
Q. A particle moves along a straight line. Its position at any instant is given by x=32t−8t33 where x is in m and t in s. The acceleration of the particle at the instant when particle is at rest will be
- −16 m/s2
- −32 m/s2
- 16 m/s2
- 32 m/s2
Q. The displacement x of a particle depends on time t as x=αt2−βt3. Then,
- The particle will return to its starting point after time αβ
- The particle will come to rest after time 2α3β
- The initial velocity of the particle was zero but its initial acceleration was not zero
- No net force will act on the particle at t=α3β
Q. Velocity of the particle in a rectillinear motion is given as v=2t2−5t in m/s. Find
(i) Acceleration at 4 sec.
(ii) Average accleration in 4 sec.
(i) Acceleration at 4 sec.
(ii) Average accleration in 4 sec.
- (i) 11 m/s2
(ii) 3 m/s2 - (i) 7 m/s2
(ii) 2 m/s2 - (i) 17 m/s2
(ii) 6 m/s2 - (i) 16 m/s2
(ii) 7 m/s2
Q. A particle is moving along x-axis whose instantaneous speed is v=√108−9x2. The acceleration of the particle is
- −9x m/s2
- −18x m/s2
- −9x2 m/s2
- None of these