Instantaneous velocity
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Q. A car moves along a straight line whose equation of motion is given by s=24t+3t4–2t3, where s is in metre and t is in second. The velocity of the car at t=0 will be
- 7 m/s
- 9 m/s
- 12 m/s
- 24 m/s
Q. Starting from rest a particle moves in a straight line with acceleration a={2+|t−2| m/s2}. What will be the velocity of particle in m/s at the end of 4 s?
Q. A particle starting from rest undergoes acceleration given by a=|t–2| m/s2 where, t is time in second. Velocity of particle after 4 sec is
- 1 m/s
- 2 m/s
- 8 m/s
- 4 m/s
Q. PSLV launches a rocket in a gravity free space with constant acceleration 5 m/s2 along +x direction (see figure). The length of the chamber inside the rocket is 6 m. At time t=0, a ball is thrown from the left end of the chamber in +x direction with a speed 0.7 m/s relative to the rocket. At the same time, another ball is thrown in opposite direction to the previous ball with a speed 0.3 m/s relative to the rocket. The time in seconds when the two balls hit each other is
Q. The position of the particle is given by x=(et−cost) in m. The velocity (in m/s) of the particle as a function of time t is
- et−sint
- et−sect
- et+tant
- et+sint
Q. The instantaneous velocity of a particle moving in a straight line is given as v=αt+βt2, where α and β are constants. The distance travelled by the particle between 1 s and 2 s is
- 3α+7β
- 32α+73β
- α2+β3
- 32α+72β
Q. Starting from rest a particle moves in a straight line with acceleration a={2+|t−2| m/s2}. What will be the velocity of particle in m/s at the end of 4 s?
Q. A particle starts from rest. Its acceleration at time t=0 is 5 ms−2 which varies with time as shown in figure. The maximum speed of the particle will be
- 7.5 ms−1
- 15 ms−1
- 30 ms−1
- 7.5 ms−1
Q. The rate change of displacement with time is .
- speed
- velocity
- acceleration
Q. How small is an instant?
- Very small time interval
- Zero time interval
- Infinitesimally small time interval
- Not defined
Q. Statement -1 : Let v be the speed of particle at any time t. If dvdt is a non - zero constant then speed of particle may be minimum at some time.
Statement -2 : The speed v of a moving particle may be minimum at time t=t0 when v=0. The speed v of a moving particle may also be minimum at time t=t0 when dvdt=0 and d2vdt2= positive.
Statement -2 : The speed v of a moving particle may be minimum at time t=t0 when v=0. The speed v of a moving particle may also be minimum at time t=t0 when dvdt=0 and d2vdt2= positive.
- Both statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1.
- Both statement 1 and statement 2 are correct but statement 2 is not the correct explanation of statement 1.
- Statement 1 is correct and statement 2 is incorrect.
- Statement 1 is incorrect and statement 2 is correct.