Intro to Simple Pendulum
Trending Questions
Q. a particle execute SHM of amplitude 5cm has max speed of 31.4cm the frequenvy of oscillation is
Q. With what minimum speed a particle be projected from the origin so that it is able to pass through a given point (30m, 40m)?
Q. Why does l become R in the formula: T=2π√R/g, in the case where length of simple pendulum is very much larger than Radius of Earth?
Q. for a damped oscillator , the mass m of the block is 400g, k=45N/m and the damping cons†an t b is 80g/s.calculate time taken for its amplitude if vibrations to drop to half if its initial value
Q. A simple pendulum pulled a side through an angle θ and released. The tension at the mean position is
1) mg(3 + 2cos θ) 2) mg(3 – 2cosθ) 3) mg(3 – cos θ) 4) mg(2 – cos θ)
1) mg(3 + 2cos θ) 2) mg(3 – 2cosθ) 3) mg(3 – cos θ) 4) mg(2 – cos θ)
Q. if the amplitude of oscillation of a simple pendulum is increased by20%, then percentage change in the time period will b
Q. A block of mass 0.02 kg is connected with spring and is free to oscillate on a horizontal smooth surface as shown. The angular frequency of oscillation is 2rad/s
The block is pulled by 4cm and then pushed toward the spring with a velocity of 8cm/s .the amplitude of oscillation is
Q. In a simple pendulum, length increases by 4% andg increases by 2%, then time period of simplependulum(1) Increases by 4%(2) Increases by 3%(3) Decreases by 3%29(4) Increases by 1%
Q. 34. A simple pendulum cross the highest point of a vertical circle with critical speed .What will be the centripetal acceleration of the bob and the string is horizontal?
Q. 61.A body weighing 150 newtons moves with a simple harmonic motion. The velocity and acceleration of the body when it is 200mm from the center of oscillation are 5 meter/sec anf 20 meter /sec square. Find amplitude of motion and number of vibration per minute
Q. The metalic bob of a simple pendulum has the relative density ρ . The time period of this pendulum is T . If the metallic bob is immeresed in water then the new tme period is given by
Q. Two particles having same time period, same amplitude, same mean position and their shadows are oscilating on the same straight line, are moving such that at T=0 one is at the mean position , and other is at the extreme position.
1. Calculate the time when they will of cross each other .
2. Calculate their maximum separation.
3. Calculate the time when they will have maximum separation
Q. A particle is executing shm about y=0 along y axis. its position at an instant is given by y = 5sin3πt + 5cos3πt the amplitude of oscillation is
Q. 4.The mass and diameter of a planet are twice those of earth. The period of oscillation of pendulum on this planet will be
Q. A simple pendulum is oscillating without damping. When the bob is at extreme position, acceleration vector is correctly shown by
Q. The displacement of a harmonic oscillator is givenby x =oscillator isasinot Bcosot. The amplitude of the ossccillato(1) a(2) B(4) 2+2(3) a+ B
Q. A simple pendulum is oscillating without damping. When the displacement of the bob is less than maximum, its acceleration vector →a is correctly shown in (see figure.)
Q. The bob of a pendulum is released from a horizontal position. If the length of the pendulum is 1.5m, what is the speed with which the bob arrives at the lowermost point, given that it dissipated 5% of its initial energy against air resistance ?
Q. A simple pendulum with a brass bob has a time period T. The bob is now immersed in a non-viscous liquid and oscillated. If the density of the liquid is 18 that of brass, the time period of the same pendulum will be
- √87T
- 87T
- 8272T
- T
Q. The bob of simple pendulum having density 40003 kg/m3 executes SHM in water with a period ′t′ s. If the period of oscillation of bob in air is 10 s, find the value of ′t′.
(Neglect frictional force of water, take density of water as 1000 kg/m3)
(Neglect frictional force of water, take density of water as 1000 kg/m3)
- 10
- 20
- 30
- 40
Q. A physical quantity Z as a function of time is given as Z(t) = A3/2 e-kt,
where k = 0.1 s-1. The measurement of A has an error of 2.00%. If the
error in the measurement of time is 1.25%, then the percentage error
in the value of Z(t) at t = 10 s would be
4.25%
2.50%
3.75%
3.50%
Q.
the frequency of vibration of string is given by f= p/2l [F/m]1/2.Here p is is the no of segments in the string and l is the length.What is the dimensional formula of m?
Q. Solve this:
Question
If a simple pendulum completes 20 oscillations in 50 seconds, where the time is measured by a stopwatch of least count 0.2 second. Then percentage error in measurement of time period is
A. 0.8 %
B. 0.2 %
C. 1.6 %
D. 0.4 %
Question
If a simple pendulum completes 20 oscillations in 50 seconds, where the time is measured by a stopwatch of least count 0.2 second. Then percentage error in measurement of time period is
A. 0.8 %
B. 0.2 %
C. 1.6 %
D. 0.4 %
Q.
A simple pendulum attached to the ceiling of a stationary lift has a time period T. The distance y covered by the lift moving upwards varies with time t as y=t2 where y is in metre and t in second. If g=10ms−2, the time period of the pendulum will be
√45T
√56T
√54T
√65T
Q. A PARTICLE EXECUTES WITH TIME PERIOD 12 S .FIND THE TIME TAKEN BY THE PARTICLE TO GO DIRECTLY FROM ITS MEAN POSITION TO HALF ITS AMPLITUDE?
Q. A simple pendulum is made of a body which is a hollow sphere containing mercury, suspended by means of a wire. If a little mercury is drained off, then the time period of pendulum
- Decrease
- Increase
- Remains unchanged
- Become erratic
Q. a stone tied to the end of a string of 1m long is whorled in a horizontal circle with constant speed if the stone makes 22 revolution in 44 s what is the magnitude and direction of accelaration of the stone