Magnetic Flux and Faraday's Law
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A table with smooth horizontal surface is turning at an angular speed ω about its axis. A groove is made on the surface along a radius and a particle is gently placed inside the groove at a distance a from the centre. Find the speed of the particle as its distance from the centre becomes L.
v = L
v =
v = a
v =
- 1.2 A
- 0.2 A
- 0.6 A
- 0.8 A
- 2π(R0+t)B clockwise
- π(R0+t)B clockwise
- 2π(R0+t)B anticlockwise
- Zero
- Plate 1 will be negative and plate 2 positive
- Plate 1 will be positive and plate 2 negative
- Both the plates will be positive
- Both the plates will be negative
- BVR clock wise
- BVR anti clock wise
- 2BVR Anti -clock wise
- Zero
A conducting square loop of side L and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. It is sorrounded by a magnetic field B which is constant in time and space and is pointing perpendicularly into the plane of the loop. The current induced in the loop is
Zero
The graph of magnitude of induced emf in the coil is represented by
- Is zero
- Decreases as 1r
- Increases as r
- Decreases as 1r2
- 3×10−4 V/m
- 6.25×10−4 V/m
- 4.5×10−4 V/m
- 9.25×10−4 V/m
- BVR clock wise
- BVR anti clock wise
- 2BVR Anti -clock wise
- Zero
- μ0bIπτln(d+ad)
- μ0bI2πτln(d+aa)
- 2μ0bIπτln(d+aa)
- μ0bIπτln(dd+a)
A square loop of side 4 cm is lying on a horizontal table. A uniform magnetic field of 0.5 T is directed downwards at an angle of 60o to the vertical as shown in Fig. 25.3. If the field increases from zero to its final value in 0.2 s, the emf induced in the loop will be
1 mV
2 mV
3 mV
4 mV
- Is zero
- Decreases as 1r
- Increases as r
- Decreases as 1r2
- 32 volt
- 8 volt
- 16 volt
- zero
- 0.4 V
- 0.8 V
- 0.6 V
- 1.0 V
- 20 ms
- 0.02 ms
- 2 ms
- 0.2 ms
- 0.8 mV
- 0 V
- 0.2 mV
- 0.4 mV