New Capacitance in Dielectric
Trending Questions
Q. The radius of a thin wire is 0.16 mm. Thearea of cross-section taking significantfiguremillimetres isintoconsideration0Zinsquare
Q. Three different dielectrics are filled in a parallel plate capacitor as shown. What should be the value of dielectric constant of a material , which when fully filled between the plates produces same capacitance ? (Asssume terminals are connected between AC and BD).
- 6
- 9
- 4
- 5
Q.
The capacity of a parallel plate condenser is . When a glass plate is
placed between the plates of the conductor, its potential becomes 1/8thof
the original value. The value of dielectric constant will be
1.6
5
8
40
Q. Three different dielectrics are filled in a parallel plate capacitor as shown. What should be the value of dielectric constant of a material , which when fully filled between the plates produces same capacitance ? (Asssume terminals are connected between AC and BD).
- 5
- 6
- 9
- 4
Q. A parallel plate air condenser has a capacity ‘C’. When the plate separation is halved and a dielectric of constant k is inserted, new capacitance is found to be 12C. The value of dielectric constant ‘k’ is?
- 12
- 24
- 6
- 3
Q. The dimension of Eo E^2/2 (Eo is permittivity of free space; E: electric field) is?
Q. A capacitor is formed by two square metal plates of edge 1 m, separated by a distance 1 mm. Dielectrics of dielectric constant K1 and K2 are filled in the gap as shown in figure. The new capacitance is
[ Take ln2=0.7 ]
[ Take ln2=0.7 ]
- 15 nF
- 25 nF
- 10 nF
- 20 nF
Q. I have an insulator with dielectric constant k. If I place it in a region in vacuum with a field E. Then the net field inside the dielectric will be?
- Ek
- Ek
- Ek2
- Ek2
Q. Two parallel-plate capacitors, each of capacitance 40μF, are connected in series. The space between the plates of one capacitor is filled with a dielectric of dielectric constant K=3, then the equivalent capacitance of the combination is
- 30μF
- 120μF
- 40μF
- 160μF
Q. The plates of a parallel plate capacitor are charged up to 100 V. Now, after removing the battery, a 2 mm thick plate is inserted between the plates . Then, to maintain the same potential difference, the distance between the capacitor plates is increased by 1.6 mm. The dielectric constant of the plate is
- 2.5
- 4
- 5
- 1.25
Q. The plates of a parallel plate capacitor are charged up to 100 V. Now, after removing the battery, a 2 mm thick plate is inserted between the plates . Then, to maintain the same potential difference, the distance between the capacitor plates is increased by 1.6 mm. The dielectric constant of the plate is
- 5
- 1.25
- 4
- 2.5
Q. A parallel plate condenser has a capacitance 50μF in air and 110μF when immersed in an oil. The dielectric constant of the oil is?
0.45
0.55
1.10
2.20
Q. A dielectric slab of dielectric constant k=5 is placed between plates of parallel plate capacitor, thickness of slab is 30% of plate spacing & its area is same as that of the plates, new capacitance is C′ & old capacitance was C. The ratio C′C is approximately equal to
- 54
- 35
- 75
- 43
Q. When a capacitor of capacitance C is filled with a dielectric (i.e. thickness of the dielectric is equal to the spacing between the plates) of dielectric constant k, what is the new capacitance?
- Ck
- Ck
- Ck2
- Ck2
Q. The figure shows a parallel plate capacitor with charge Q1 and plate area A. Capacitor is filled with two dielectrics k1 and k2 as shown.
- Ratio of energy density in first dielectric to second dielectric is 53
- Ratio of energy stored in the two dielectrics is 1 : 1
- Surface charge at interface of the two dielectrics is 2Q15
- Surface charge at interface of the two dielectrics is 0.
Q. A capacitor is formed by two square metal plates of edge 1 m, separated by a distance 1 mm. Dielectrics of dielectric constant K1 and K2 are filled in the gap as shown in figure. The new capacitance is
[ Take ln2=0.7 ]
[ Take ln2=0.7 ]
- 25 nF
- 10 nF
- 20 nF
- 15 nF
Q. When a dielectric material is introduced between the plates of a charges condenser, then electric field between the plates
[Pb PMT 2004]
[Pb PMT 2004]
- Remain constant
- Decreases
- Increases
- First increases then decreases
Q. Figure shows a parallel plate capacitor having square plates of edge length a and separation d. The gap between the plates is filled with a dielectric of dielectric constant K which varies parallel to an edge as, K=Ko+αx
Where, K and α are constants and x is the distance from the left end. Calculate the capacitance of system.
Where, K and α are constants and x is the distance from the left end. Calculate the capacitance of system.
- ϵoaKoα2d
- ϵoa2Kod
- ϵoa2(Ko+aα)2
- ϵoa2d(Ko+aα2)
Q. A hemispherical earth plate is buried into the earth. Find the potential difference between the feet of a man standing on ground as shown in figure. Current through earth plate is I. Conductivity of earth is [δ=10−3π, I=1A] (up to two decimal places)