Radial & Tangential Acceleration for Non Uniform Circular Motion
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A coin placed on uniformly rotating turntable just slips if it is placed at a distance of 4 cm from the centre. If the angular velocity of the turntable is doubled, it will just slip at a distance of
2 cm
1 cm
8 cm
4 cm
Let 1.00 kg of liquid water at 100∘C be converted to steam at 100∘C by boiling at standard atmospheric pressure (which is 1.00 atm or 1.01 × 105 Pa) in the arrangement as shown. The volume of that water changes from an initial value of 1.00×10−3 m3 as a liquid to 1.671 m3 as steam.
1. How much work is done by the system during this process?
4200 kJ
100 kJ
169 kJ
4.2 kJ
- √7gl
- √5gl
- √3gl
- √4gl
A pendulum clock loses 12 seconds a day if the temperature is 40∘C and goes fast by 4 seconds a day if the temperature is 20∘C. Find the temperature at which the clock will show correct time, and the coefficient of linear expansion of the metal of the pendulum shaft.
;
;
;
;
- 2mg
- 4mg
- 8mg
- 6mg
- When the mass is at height B.
- When the mass is at the lowest point.
- When the wire is horizontal.
- At an angle of 30∘ from the upward vertical.
- T=mg(2cosθ−3cosθ0), θmax=30∘
- T=mg(3cosθ−2cosθ0), θmax=60∘
- T=mg(3cosθ−2cosθ0), θmax=30∘
- T=mg(2cosθ−3cosθ0), θmax=60∘
- 400 W
- 1000 W
- 500 W
- 0 W
- 2g3
- g3
- √53g
- Ball never leaves contact
- 25 m/s2
- 25 rad/s2
- 2500π2 m/s2
- 2500π2 rad/s2
- 5√2 rad/s
- 5 rad/s
- 2√2 rad/s
- 2 rad/s
- 6.47 m/s
- 10 m/s
- 0 m/s
- 15 m/s
- −12θ0 rad/s2
- 2−6θ0 rad/s2
- 4−12θ0 rad/s2
- 4−3θ0 rad/s2
- 37∘
- 53∘
- 60∘
- 45∘
- 0 m/s
- 20 m/s
- 10 m/s
- 5 m/s
Match the block diagrams of blocks of mass m with their corresponding free body diagram
(Bodies are at rest w.r.t. ground)
P - (i); Q - (iv); R - (vi); S - (vii)
P - (ii); Q - (iv); R - (vi); S - (viii)
P - (iii); Q - (v); R - (v); S - (viii)
P - (iii); Q - (iv); R - (vi); S - (v)
- 500 N
- 1000 N
- 500√2 N
- 500√2 N
- At the top of the circle.
- At the bottom of the circle.
- Half way down
- None of above
- infinitesimal
- μ√α
- 1√μα
- √μα
- 6.47 m/s
- 10 m/s
- 0 m/s
- 15 m/s
- ω=120e−θ
- ω=120eθ
- ω=60e−θ
- ω=60eθ
- Is directly proportional to time
- Is constant with time
- Is inversely proportional with time
- Cannot be determined as data is insufficient
- 200, 5
- 50, 10
- 100, 5
- 200, 10
- θ=cos−1(13)
- θ=60∘
- θ=cos−1(23)
- θ=0∘
A proton of mass 1.6×10−27 kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4×10−13N. then the frequency of revolution of the proton is about
0.08×108 cycles per sec
4×108 cycles per sec
8×108 cycles per sec
12×108 cycles per sec
Figure
(a) The velocity of the particle is constant.
(b) The acceleration of the particle is constant.
(c) The magnitude of acceleration is constant.
(d) The magnitude of acceleration is decreasing continuously.
- 20 s
- 20√3 s
- 20√5 s
- 10√10 s
- 29 rad
- 23 rad
- 25 rad
- 27 rad
- ω=120e−θ
- ω=120eθ
- ω=60e−θ
- ω=60eθ