Restoring Force
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The potential energy of a system is represented as shown in the figure. The force acting on the system will be represented by
The potential energy for a force field ¯F is given by ∪(x, y) = cos(x+y). The force acting on a particle at position given by coordinates (0, π/4) is
- 1√2 (^i+^j)
1√2 (^i+^j)
( 12^i + √32^j )
( 12^i - √32^j )
- −0.5 m/s
- −1 m/s
- 1 m/s
- 2.5 m/s
- −GMR[1√2+2√5]
- −GMR[1+1√2]
- −GMR[1√2−2√5]
- Zero
- −0.5 m/s
- −1 m/s
- 1 m/s
- 2.5 m/s
The potential energy of a system is represented as shown in the figure. The force acting on the system will be represented by
A particle which is constrained to move along the x-axis, is subjected to a force in the same direction which varies with the distance x of the particle from the origin as F(x)=−kx+ax3. Here k and a are positive constants. For x≥0, the functional from of the potential energy U(x)of the particle is
The potential energy for a force field ¯F is given by ∪(x, y) = cos(x+y). The force acting on a particle at position given by coordinates (0, π/4) is
- 1√2 (^i+^j)
1√2 (^i+^j)
( 12^i + √32^j )
( 12^i - √32^j )
The potential energy of a system is represented as shown in the figure. The force acting on the system will be represented by
A particle which is constrained to move along the x-axis, is subjected to a force in the same direction which varies with the distance x of the particle from the origin as F(x)=−kx+ax3. Here k and a are positive constants. For x≥0, the functional from of the potential energy U(x)of the particle is [IIT JEE 2002]