Spring Block's Time Period
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(Assume that the dimensions of the cube is much less than 60 cm)
(K1=1.8 N/m, K2=3.2 N/m, m=200 gm)
- 1.41 s
- 2.83 s
- 5.64 s
- 1.92 s
A mass m = 2.0 kg is attached to a spring having a force constant k = 290 N/m as in the figure. The mass is displaced from its equilibrium position and released. Its frequency of oscillation (in Hz) is approximately:
1.9
0.50
0.01
12
A particle moving along the x-axis executes simple harmonic motion, then the force acting on it is given by
[CBSE PMT 1994]
- A Kx
A cos (Kx)
A Kx
A exp (- Kx)
Value of spring constant depends upon
Elastic properties of the spring
Number of turns
Length of spring
Mass attached to spring
- √52π
- 4π√5
- 2π√3
- √5π
Two springs of force constants K1 and K2 are connected to a mass m as shown. The frequency of oscillation of the mass is f. If both K1 and K2 are made four times their original values, the frequency of oscillation becomes:
f4
4f
2f
f2
Four blocks and two springs are arranged as shown in figure. The system is at rest. Determine the acceleration of all the loads immediately after the lower thread keeping the system in equilibrium has been cut. Assume that the thread and pulleys are weightless and there is no friction at the point of suspension.
= 0
= 0
= 0
upwards
= g downloads
= g downloads
= g upwards
upwards
= 0
= 0
= 0
upwards
= g uploads
= g uploads
= g downwards
downwards
- time period does not change
- amplitude increases
- time period decreases
- time period increases
- 2π√m4k
- 2π√m2k
- 2π√mk
- 2π√m8k
- Mgk(1+LAσM)
- Mgk(1−LAσ2M)
Mgk
- Mgk(1−LAσM)