Subtraction of a Vector
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A plane is revolving around the earth with a speed of 100 km/hr at a constant height from the surface of earth. The change in the velocity as it travels half circle is
200 km/hr
150 km/hr
100√2km/hr
0
If →B is added to →A, the result is 6.0^i+1.0^j.If →Bis subtracted from →A, the result is −4^i+7.0^j. What is the magnitude of →A?
The magnitudes of vectors →A, →Band→C are 3, 4 and 5 units respectively. If →A+→B=→C, the angle between →A and →B is
π2
cos−1(0.6)
tan−1(75)
π4
If Sameer moves from point A having position vector 3^i+2^j+5^k to point B having position vector 6^i+3^j+7^k, what is his displacement vector?
3^i+^j+3^k
3^i+^j+2^k
3^i+^j+4^k
3^i+^j+7^k
- (1+√3)^i+2^j
- (1+√3)^i−2^j
- (1−√3)^i+2^j
- (1−√3)^i
If Sameer moves from point A having position vector 3^i+2^j+5^k to point B having position vector 6^i+3^j+7^k, what is his displacement vector?
3^i+^j+3^k
3^i+^j+2^k
3^i+^j+4^k
3^i+^j+7^k
- 0
- 5^i+5^j
- 5^j
- 5^i
- P =2Q
- P =Q
- PQ=1
- None of these
- Perpendicular
- Parallel
- Antiparallel
- Inclined at an angle of 60∘
A scooter going due east at 10ms−1 turns right through an angle of 90°. If the speed of the scooter remains unchanged in taking turn, the change is the velocity of the scooter is
20.0ms−1 south eastern direction
Zero
10.0ms−1 in southern direction
14.14ms−1 in south-west direction
- 0
- 5^i+5^j
- 5^j
- 5^i
What is the angle between →P and the resultant of (→P+→Q) and (→P−→Q)
Zero
tan−1(PQ)
tan−1(QP)
tan−1(P−QP+Q)
- Perpendicular
- Parallel
- Antiparallel
- Inclined at an angle of 60∘