The De Broglie Explanation

Q. Explain the Ampere and Faraday observation i.e, the electron charges in the motion produce magnetic fields and moving magnet generate electricity.

Q. The de-Broglie wavelength of an electron in first orbit of Bohr's hydrogen is equal to

1. radius of the orbit
2. perimeter of the orbit
3. diameter of the orbit
4. half of the perimeter of the orbit

Q. One of the lines in the emission spectrum of ${\text{Li}}^{2+}$ has the same wavelength as that of $2^{nd}$ line of Balmer series in hydrogen spectrum. The electronic transition corresponding to this line is :-

1. $n=12\to n=6$
2. $n=4\to n=2$
3. $n=8\to n=4$
4. $n=8\to n=2$

Q. According to De Broglie the electron in n=3 of $L{i}^{++}$ atom will look like

1. 
2. 
3. 
4. 

Q. What is the de Broglie wavelength of an electron with a kinetic energy of $120\text{eV}$?
(Given: $h=6.63\times {10}^{-34}\text{Js},m_e=9.11\times {10}^{-31}\text{kg},e=1.6\times {10}^{-19}\text{coulomb}$

1. $725\text{pm}$
2. $500\text{pm}$
3. $322\text{pm}$
4. $112\text{pm}$

Q.

According to De Broglie 2$\pi$r=n$\lambda$ where n is the quantum number of an orbit, in visual representation of an electron as a wave, n stands for:

1. No. of loops , where one loop is one wavelength

2. No. of electrons

3. No. of half wavelengths

4. Can not comment