Velocity Displacement Relationship
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The equation of a progressive wave is given by y=asin (628t − 31.4x) If the distances are expressed in cms and time in seconds, then the wave velocity will be
[DPMT 1999]
314 cm/sec
400 cm/sec
20 cm/sec
628 cm/sec
- √52π
- 4π√5
- 2π√3
- √5π
The second hand of a clock is 2.0 cm long .calculate the speed of the tip of the hand, the velocity at 0 seconds and at 15 seconds, the change in velocity from 0.0 to 15 seconds, and average acceleration.
For a simple pendulum, the graph between g and T2 will be
Circle
Square
Hyperbola
Straight line
A car travelling at 36km/h-1 due North turns West in 5 seconds and maintains the same speed. What is the acceleration of the car?
4ms-2South West
2√2 ms-2South West
2ms-2South West
√2ms-2South West
- 80 cm/s
- 16 cm/s
- 60 cm/s
- 25 cm/s
If a cycle wheel of radius completes one revolution in , then the acceleration of a point on the circumference of the wheel will be
The instantaneous displacement of a simple harmonic oscillator is given by y = A cos (ωt + n/4). Its speed will be maximum at the time:
n/4ω
2n/ω
ω/n
ω/2n
[A= amplitude of SHM]
- v04
- √32v0
- 3v02
- v0√2
Mass A is connected with a string which passes through a fixed pulley. The other end of the string is connected with a movable pulley N. The block B is connected with another string which passes through the pulley N as shown in figure. Find the relation between acceleration of A & B.
A body starts from origin and moves along x - axis such that at any instant velocity is vt = 4 t3 - 2t where t is in seconds vt is m s−1 .
The acceleration of the particle when it is 2 m from the origin is 11 x m s−1 , where x is
3
2
7
0
Derive the expression for the distance travelled in nth second of a uniformly acceleratad motion.