Vernier Caliper

Q.

The diameter of a cylinder is measured using a Vernier calipers with no zero error. It is found that the zero of the Vernier scale lies between 5.10 cm and 5.15 cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45 cm. The ${24}^{th}$ division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is

1. 5.112 cm

2. 5.136 cm

3. 5.148 cm

4. 5.124 cm

Q. A vemier callipers has 20 divisions on the vernierscale which coincide with 19 divisions on the mainscale. The least count of the instrument is 0.1 mm.The main scale divisions are of54.(1) 0.5 mm(2) 1 mm(3) 2 mm(4) 1/4 mm

Q. the vernier scale of a callipers has 50 divisions which coincide with 49 main scale divisions.if each main scale division is of 0.5 mm, then the minimum inaccura cy in the measurement by calliers is ?

Q. In a vernier callipers, one main scale division is 1mm and 9 main scale divisions are equal to 10 vernier scale divisions . When nothing is put between jaws of the callipers , zero of the vernier scale lies to the right side of zero of the main scale and the 2nd division of the vernier scale coincides with a main scale division. While measuring inner diameter of a hollow cylinder the zero of vernier scale lies between 1.7 cm and 1.8 cm of the main scale. Also, 8th division of the vernier scale coincides with a main scale division . Inner diameter of the cylinder is

Q. If 19 main scale divisions coincides with20 vernier scale divisions. The least count will be(1 main scale division = 1 mm)

Q. In a vernier calipers , one main scale division is $x\text{cm}$ and $n$ divisions of the vernier scale coincide with $(n-1)$ divisions of main scale. The least count (in $\text{cm}$) of the caliper is:

1. $\left(\frac{n-1}{n}\right)$
2. $\frac{nx}{(n-1)}$
3. $\frac{x}{n}$
4. $\frac{x}{x-1}$

Q. 2. In a Vernier Calliper length of 10 main scale division is 2 mm 20 vernier scale division coincide with 10 main scale division then the least count of instrument is

Q. The main scale of a vernier caliper read in mm and its vernier is divided into 10 divisions which coincide with 9 divisions of the main scale . the reading for the situation is found to be x/10 mm find the value of x in 1) 8th div of V.S. coincide with M.S.D. & 2)6th div. Of V.S. coincide with M.S.D.

Q. The main scale of a vernier callipers is calibrated in mm and 19 divisions of main scale are equal in length to 20 divisions of vernier scale. In measuring the diameter of a cylinder by this instrument, the main scale reads 35 divisions and 4th division of vernier scale coincides with a main scale division. Find:(i) least count and (ii) radius of cylinder.

Q. In a vernier calipers , one main scale division is $x\text{cm}$ and $n$ divisions of the vernier scale coincide with $(n-1)$ divisions of main scale. The least count (in $\text{cm}$) of the caliper is:

1. $\left(\frac{n-1}{n}\right)$
2. $\frac{nx}{(n-1)}$
3. $\frac{x}{n}$
4. $\frac{x}{x-1}$

Q.

Find the least count of a vernier caliper whose 50 vernier scale divisions match with 49 main scale divisions?

Given: least count of main scale is 1 mm.

1. 0.1 mm

2. 0.02 mm

3. 0.05 mm

4. 0.001 mm

Q. in a vernier capillar , one main scale division is x cm and n divisions of the vernier scale coincides with (n-1) divisions of the main scale .the least count (in)

Q. While measuring the zero error of a vernier we see that zero of vernier scale is to the right of the zero marking of the main scale with $6^{th}$ vernier division coinciding with main scale divisions. If the least count of the vernier is 0.1 mm then find its zero error and the correction reuired in the measurements made by it.

1. Zero error = 6mm and Correction = 6mm
2. Zero error = 6mm and Correction = -6mm
3. Zero error = 0.6mm and Correction = 0.6mm
4. Zero error = 0.6mm and Correction = -0.6mm

Q. For the arrangement shown in figure, pulleys andstrings are ideal. Find out the acceleration of 2 kgblock2 kg1 kg45^° 459g 2(1)3(2)32g(4) 22g(3)3

Q. The main scale of a vernier caliper read in mm and its vernier is divided into 10 divisions which coincide with 9 divisions of the main scale . the reading for the situation is found to be x/10 mm find the value of x in 1) 8th div of V.S. coincide with M.S.D. & 2)6th div. Of V.S. coincide with M.S.D.

Q. If the Zero error of a Vernier Caliper is zero, then

1. Measured length = actual length
2. Measured length > actual length
3. Measured length < actual length
4. Measured length > = actual length

Q. In an instrument, there are 25 divisions on the vernier scale which coincides with 24th division of the main scale. 1 cm on main scale is divided into 20 equal parts. The least count of the instrument is

1. $0.002\text{cm}$
2. $0.05\text{cm}$
3. $0.001\text{cm}$
4. $0.02\text{cm}$

Q.

The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between $5.10\text{cm}$ and $5.15\text{cm}$ of the main scale. The Vernier scale has $50$ divisions equivalent to $2.45\text{cm}$. The ${24}^{\text{th}}$ division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is

1. $5.136\text{cm}$

2. $5.148\text{cm}$

3. $5.112\text{cm}$

4. $5.124\text{cm}$

Q.

MODELING REAL LIFE The hour hand of a clock moves $-30°$ every hour. How many degrees does it move in $2\frac{1}{5}$ hours?

Q. In a vernier calipers $10$ smallest divisions of the vernier scale are equal to $9$ smallest divisions of the main scale. If the smallest division of the main scale is half millimeter, then the vernier constant is:

1. $0.005\text{mm}$
2. $0.05\text{mm}$
3. $0.5\text{mm}$
4. $0.01\text{mm}$

Q. The smallest division on the main scale of a Vernier callipers is $1\text{mm}$ and 10 vernier divisions coincide with 9 main scale divisions. While measuring the diameter of a ring, the zero mark of the vernier scale lies between $5.0\text{cm}$ and $5.1\text{cm}$ and the eighth division of the vernier scale coincides with a main scale division. The diameter of the ring is :

1. $5.06\text{cm}$
2. $5.08\text{cm}$
3. $5.04\text{cm}$
4. $5.02\text{cm}$

Q. 50. In a hypothetical vernier calipers 10 equal divisions on the vernier scale coincide with 6 main scale division if one division of main scale is .5 mm then the least count is.

Q. A Vernier caliper has 1 mm marks on the main scale. It has 20 equal divisions on the Vernier scale which match with 16 main scale divisions. For this Vernier caliper, the least count is:

1. 0.02 mm

2. 0.05 mm

3. 0.1 mm

4. 0.2 mm

Q. A vernier caliper has $1\text{mm}$ marks on the main scale. It has $20$ equal divisions on the vernier scale which match with $16$ main scale divisions. For this vernier caliper, the least count is

1. $0.02\text{mm}$
2. $0.05\text{mm}$
3. $0.1\text{mm}$
4. $0.2\text{mm}$

Q. Which of the following is the most precise device for measuring length : (a) a vernier callipers with 20 divisions on the sliding scale (b) a screw gauge of pitch 1 mm and 100 divisions on the circular scale (c) an optical instrument that can measure length to within a wavelength of light ?

Q.

The side of a cube is measured by a vernier caliper (10 divisions of a vernier scale coincide with 9 divisions of main scale, where 1 division of main scale is 1 mm). The main scale reads 10 mm and first division of vernier scale coincides with the main scale. Mass of the cube is 2.736g. Find the density of the cube in appropriate significant figures.

[IIT JEE 2005]

1. $2.6g/c{m}^3$

2. $2.655g/c{m}^3$

3. $2.65g/c{m}^3$

4. None of these

Q. In an instrument, there are 25 divisions on the vernier scale which coincides with 24th division of the main scale. 1 cm on main scale is divided into 20 equal parts. The least count of the instrument is

1. $0.002\text{cm}$
2. $0.05\text{cm}$
3. $0.001\text{cm}$
4. $0.02\text{cm}$

Q. How the vernier scale reading is calculated

Q. In an experiment the angles are required to be measured using an instrument. 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the smallest division of the main scale is half-a-degree $\left(0.5°\right)$ then the least count of the instrument is

1. one minute
2. half minute
3. one degree
4. half degree

Q. A vernier caliper has $1\text{mm}$ marks on the main scale. It has $20$ equal divisions on the vernier scale which match with $16$ main scale divisions. For this vernier caliper, the least count is

1. $0.02\text{mm}$
2. $0.05\text{mm}$
3. $0.1\text{mm}$
4. $0.2\text{mm}$