Work Done, Varying Force and Path
Trending Questions
Q. The force exerted by a compression device is given by F(x)=kx(x−l), where l is the maximum possible compression, x is the compression and k is a constant. The work required to compress the device by a distance d will be maximum when
- d=l4
- d=l√2
- d=l2
- d=l
Q. A bullet of mass 10−3 kg strikes an obstacle and moves at 60∘ to its original direction. If its speed also changes from 20 m/s to 10 m/s. Find the magnitude of impulse acting on the bullet.
- √5×10−2 Ns
- √3×10−2 Ns
- √2×10−2 Ns
- 2×10−2 Ns
Q.
A body of mass 3 kg is under a force, which causes a displacement in it is given by S=t33 (in m). Find the work done by the force in first 2 seconds
2 J
3.8 J
5.2 J
24 J
Q. The force exerted by a compression device is given by F(x)=kx(x−l), where l is the maximum possible compression, x is the compression and k is a constant. The work required to compress the device by a distance d will be maximum when
- d=l4
- d=l√2
- d=l2
- d=l
Q. A block of 10 kg is pulled in a vertical plane along a frictionless surface in the form of an arc of a circle of radius 10 m. A force of 200 N is applied such that tension in the string always remains along the tangential direction as shown in figure. If the block started from rest at A, the velocity at B would be:
Consider π3=1 for calculation and take g=10 m/s2)
Consider π3=1 for calculation and take g=10 m/s2)
- 10√3 m/s
- 10 m/s
- 5√3 m/s
- 3√3 m/s
Q. A bullet is fired from a gun. The force on the bullet is given by F = 600 - 2 × 105 t, where F is in Newton and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet
- 9 Ns
- Zero
- 0.9 Ns
- 1.8 Ns
Q. A block of 10 kg is pulled in a vertical plane along a frictionless surface in the form of an arc of a circle of radius 10 m. A force of 200 N is applied such that tension in the string always remains along the tangential direction as shown in figure. If the block started from rest at A, the velocity at B would be:
Consider π3=1 for calculation and take g=10 m/s2)
Consider π3=1 for calculation and take g=10 m/s2)
- 10√3 m/s
- 10 m/s
- 5√3 m/s
- 3√3 m/s