Work Done When Force Is Varying
Trending Questions
When a rubber band is stretched by a distance x, it exerts a restoring force of magnitude F=ax+bx2, where a and b are constants. The work done in stretching the upstretched rubber band by L is
aL2+bL3
12(aL2+bL3)
aL22+bL33
12(aL22+bL33)
A metallic wire of length L metres extends by l metres when stretched by suspending a weight Mg to it. The mechanical energy stored in the wire is
The displacement x of a particle moving in one dimension under the action of a constant force is related to the time t by the equation, t = √x + 3 where x is in meters and t is in seconds. The work done by the force in the first 6 seconds is
9 J
0 J
3 J
6 J
- 15 J
- 12 J
- 32 J
- −15 J
A porter lifts a suitcase weighing 20 kg from the platform and puts it on his head 2.0 m above the platform. Calculate the work done by the porter on the suitcase.
None of these
A position dependent force F=7−2x+3x2 acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m. The work done in joules is
70
270
35
135
A body of mass 3 kg is under a force, which causes a displacement in it is given by S=t33 (in m). Find the work done by the force in first 2 seconds
2 J
3.8 J
5.2 J
24 J
- mg√2μ0
- mg2√2μ0
- mgμ0
- mg2μ0
The relationship between force and position is shown in the figure given (in one dimensional case). The work done by the force in displacing a body from x = 1 cm to x = 5 cm is
20 ergs
60 ergs
70 ergs
700 ergs
F=F0(x/x0−1). Find the work done by the force in moving the particle from x=0 to x=2x0.
- 2x0(F0−1)
- x0(F0−1)
- 3x0(F0−1)
- 0
A particle, which is constrained to move along the x-axis, is subjected to a force in the same direction which varies with the distance x of the particle from the origin as F(x)=−kx+ax3. Here k and a are positive constants. For x≥0, the functional form of the potential energy U(x) of the particle is
The work done on the particle during its displacement of 12 m is
- 18 J
- 21 J
- 26 J
- 13 J
- 16 J
- 6 J
- 0 J
- 12 J
The distance x moved by a body of mass 0.5 kg due to a force varies with time t as
x=3t2+4t+5
where x is expressed in metre and t in second. What is the work done by the force in the first 2 seconds?
25 J
50 J
75 J
100 J
- −2ka2
- 2ka2
- −ka
- −ka2
- 60 J
- −60 J
- 100 J
- −100 J