Mean of Continuous Series
Trending Questions
Q.
Calculate arithmetic mean from the following data:
Marks0−1010−2020−4040−7070−100No. of Students8123064
Q. Find the mean age in years from the frequency distribution given below:
Class interval ofFrequencyage in years(fi)25−29430−351435−392240−451645−49650−55555−593Total70
Class interval ofFrequencyage in years(fi)25−29430−351435−392240−451645−49650−55555−593Total70
- 39.39
- 39.35
- 40.15
- 40.39
Q. Find the mean of the step deviations:
ClassFrequencyClass markdiui=dihinterval(fi)(xi)(xi−a)0−1004050−200−2100−20039150−100−1200−3003425000300−400303501001400−500454502002
ClassFrequencyClass markdiui=dihinterval(fi)(xi)(xi−a)0−1004050−200−2100−20039150−100−1200−3003425000300−400303501001400−500454502002
- 0
- 1188
- 250
- 250.52
Q.
Find the mean employee age from the table below. Use assumed mean method.
Age (in years)Number of employees20−252025−301530−351235−401040−451045−508
29. 67
30.75
32.43
36.83
Q. The following table shows marks secured by 140 students in an examination:
MarksNumber of students0−102010−202420−304030−403640−5020
Calculate mean marks by the step deviation method.
MarksNumber of students0−102010−202420−304030−403640−5020
Calculate mean marks by the step deviation method.
- 25
- 25.86
- 26.92
- 20.4
Q. xifi4108111291613
Find ∑fixi from the given table.
Find ∑fixi from the given table.
- 434
- 208
- 444
- Data inadequate
Q. Look at the following table below.
Class intervalClass mark0−5−−5−10−−10−1515−20
Fill in the blanks with the class marks of the corresponding class intervals.
Class intervalClass mark0−5−−5−10−−10−1515−20
Fill in the blanks with the class marks of the corresponding class intervals.
- 5, 10
- 3, 8
- 0, 5
- 2.5, 7.5
Q.
For calculating the mean of grouped data, the mid point of each class interval is chosen to represent all the observations from that class.
True
False
Q. Calculate the mean of the following data.
ClassFrequency0−10016100−20011200−3007300−40010400−5006
ClassFrequency0−10016100−20011200−3007300−40010400−5006
- 235
- 198
- 208
- 226
Q.
Class mark of a class is __________
Upper limit + lower limit
upper limit - lower limit
Q.
The class mark for a class interval while calculating the mean is its upper limit.
False
True