Diakinesis
Trending Questions
What is chiasma in meiosis?
- crossing over
- chromomeres
- synaptonemal complex
- terminalisation of chiasmata
- Diakinesis
- Mitosis
- Meiosis II
- Cytokinesis
A. Terminalisation of chiasmata
B. Crossing over
C. Synapsis
D. Disjunction of chromosomes
E. Dissolution of synaptonemal complex
- E → D → C → B → A
- C → B → E → A → D
- A → B → C → D → E
- C → B → D → E → A
What marks the end of prophase in mitosis?
Column AColumn BADiploteneiAppearance of recombination nodule and recombination between homologous chromosomesBDiakinesisiiDissolution of the synaptonemal complex and formation of the chiasmataCZygoteneiiiCompaction of chromosomesDPachyteneivTerminalisation of the chiasmataELeptotenevSynapsis and formation of the bivalent
- A-ii; B-iv; C-v; D-i; E-iii
- A-ii; B-v; C-iv; D-iii; E-i
- A-v; B-iv; C-i; D-ii; E-iii
- A-i; B-iv; C-iii; D-ii; E-v
Do primary Spermatocytes undergo mitosis?
- One, One
- One, Four
- Four, One
- Four, Four
- Leptotene
- Zygotene
- Pachytene
- Diplotene
What happens during Meiosis-I and Meiosis-II?
Why is the pachytene stage referred to as the tetrad stage?
Cristae are associated with what?
- Prophase of Mitosis
- Both prophase and metaphase of mitosis
- Prophase I during meiosis
- Prophase II during meiosis
- Duplication without separation
- Endoduplication
- Replicatin of DNA without cell division
- All of the above
- The ribosome will read over the mutated codon and continue the synthesis of the polypeptide
- The ribosome will stop at the mutated codon and synthesise a polypeptide of 25 amino acids
- The ribosome will stop at the mutated codon and synthesise a polypeptide of 24 amino acids
- Polypeptide synthesis will not occur at all
When does meiotic recombination begin?
(i) Diplotene
(ii) Pachytene
(iii) Zygotene
(iv) Diakinesis
(v) Leptotene
- (i); (ii); (iii); (iv); (v)
- (v); (iii); (ii); (i); (iv)
- (ii); (iii); (i); (v); (iv)
- (i); (iii); (ii); (v); (iv)
Reason: The number of loops is maximum during diplotene.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Both Assertion and Reason are incorrect
I. Terminalisation
II. Crossing over
III. Synapsis
IV. Disappearance of nucleolus
- I, IV, III, II
- IV, III, II, I
- III, II, I, IV
- II, I, IV, III
- Diakinesis
- Mitosis
- Meiosis II
- Cytokinesis
- 8
- 16
- 32
- 64
- 16 peg
- 8 pg
- 4 pg
- 32 pg
- Pachytene
- Diakinesis
- Zygotene
- Metaphase- I
- Mitosis
- Meiosis
- Metamorphosis
- Organogenesis
- Mitosis
- Cytokinesis
- Meiosis I
- Diakinesis
Match the substages of prophase I of first meiotic division listed in column I with the important events pertaining to respective stages given under column II; choose the answer which gives the correct combination of alphabets of the two columns:
Column I Substages of prophase I Column II Important eventsAZygotenepChromomeresBPachyteneqBivalents migrate to peripheryCDiplotenerTerminalization of chiasmata beginsDDiakinesissCrossing over tSynapsis
A = t, B = s, C = r, D = q
A = p, B = s, C = r, D = q
A = s, B = p, C = r, D = q
A = s, B = t, C = r, D = q
- telophase and metaphase
- telophase and prophase
- prophase and telophase
- prophase and anaphase
- Leptotene
- Zygotene
- Pachytene
- Diakinesis
- Diplotene
- Zygotene
- Diakinesis
- Pachytene
B. Formation of bivalent
C. Synapsis
D. Recombination
E. Movement of chiasmata
F. Chiasma formation
G. Disappearance of nucleolus
In given statements, what is the correct sequence of the process of meiosis?
- A →B →D →G →F →C →E
- E →C →D →G →F →A →B
- A →C →B →D →F→E → A
- B →C →D →G →F →A → E