Chloroform + Base Reaction with Amines
Trending Questions
Q. Why can't Lialh4 be used to reduce nitro benzene to aniline. It is a strong so shouldn't it reduce the nitro group
Q. The reaction of Q with PhSNa yields an organic compound (major product) that gives positive Carius test on treatment with Na2O2 followed by addition of BaCl2. The correct option(s) for Q is/are:
Q. Reaction of trans 2-phenyl-1-bromocyclopentane on reaction with alcoholic KOH produces major product as
Q. An organic compound ′A′(C9H10O) when treated with conc. HI undergoes cleavage to yield compounds ′B′ and ′C′. ′B′ gives yellow precipitate with AgNO3 where as ′C′ tautomerizes to ′D′. ′D′ gives positive iodoform test. ′A′ could be
Q.
An organic compound (A) on reduction gives compound (B). (B) on treatment with CHCl3 and alcoholic KOH gives (C). (C) on catalytic reduction gives N - methyl aniline. The compound 'A' is
- Methyl amine
- Ethyl amine
- Aniline
- Nitro benzene
Q. What will be the reactivity order of the following amines for carbylamine test?
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/908543/original_2q.png)
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/908543/original_2q.png)
- I>III>II>IV
- I>II>III>IV
- I>IV>II>III
- II>III>IV>I
Q.
An organic compound (A) on reduction gives compound (B). (B) on treatment with CHCl3 and alcoholic KOH gives (C). (C) on catalytic reduction gives N - methyl aniline. The compound 'A' is
- Ethyl amine
- Aniline
- Nitro benzene
- Methyl amine
Q. 11. Which of the following aryl amines undergo diazotisation most readily? 1) p-nitro aniline 2) p-chloro aniline 3) p-methoxy aniline 4) p-methyl aniline
Q.
CH3COCl+H2------->CH3CH2OH------->CH3CHO(in presence of pd, BaSO4 and quinoline).
Here quinoline acts as what?
a)+ve catalyst
b)catalyst poison
c)promoter
d)medium
Q. Ph−CH3Cl2−−→hv(A) aq. KOH −−−−−−→(B)Na−−→(C)(A)−−→(D)
The end product (D) of the given sequence is:
The end product (D) of the given sequence is:
- Ph−CH2−CH2−Ph
- Ph−CH2−O−Ph
- Ph−CH2−O−CH2−Ph
Q. Which of the following product is obtained for the controlled oxidation of propane in presence of manganese acetate?
- Propanol
- Propanone
- Propanoic acid
- Methyl acetate
Q. an organic compound A(C4H9Cl) on reactio with Na/diethyl ether gives a hydrocarbon which on monochlorination gives only one chloro derivative then A is
(a)t-butyl chloride
(b)secondary butyl chloride
(c)iso butyl chloride
(d)n-butyl chloride
Q. Aniline reacts with excess Br2/H2O to give product identify the major product:
Q. CH3CH=CH2Cl2(hv)−−−−→800∘CXNaI−−−→acetoneY
The compound Y in the above sequence is
The compound Y in the above sequence is
- 2-Dichloro-3-iodopropane
- 1-Chloro-2-iodopropane
- 3-Iodopropene
- 1, 2-Diiodopropane
Q.
How will you convert nitromethane into dimethylamine?
Q. Predict the product of the given schmidt rearrangement.
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1393232/original_33.png)
Q. Which of the following amine will give the carbylamine test?
<!--td {border: 1px solid #cccccc;}br {mso-data-placement:same-cell;}--> NEET 2020
<!--td {border: 1px solid #cccccc;}br {mso-data-placement:same-cell;}--> NEET 2020
Q. An unknown amine is treated with an excess of methyl iodide. Two equivalents of methyl iodide react with amine. The amine is treated with silver oxide and water and then heated to 120 oC. The resulting products are trimethylamine and ethylene. Identify the amine.
Q. Which of the following statement(s) is/are true about schmidt rearrangement?
- Isocyanate intermediate is formed
- It is a free radical mechanism
- Acyl ion is formed during the reaction
- Both primary and secondary amines are produced by this reaction
Q. Write the structures of the following compounds.
Di-sec-butyl ketone
Di-sec-butyl ketone
Q. Which of the following is more appropriate reason for aniline being less basic than aliphatic amines?
- Steric hindrance
- Positive mesomeric effect
- Inductive effect
- Negative mesomeric effect
Q. AnilineCHCl3/KOH−−−−−−−−→ΔXi. LiAlH4−−−−−→ii. H2OY
(Y) is:
(Y) is:
- Ph−NH−CH3
- Ph−CH2−NH2
- Ph−NH−CHO
- Ph−⊕N≡⊖C
Q. Oxidation of aldehyde and ketone by peroxybenzoic acid to ester is called:
- Wolff-Kishner reaction
- Clemmensen reaction
- Wittig ylide reaction
- Baeyer-Villiger oxidation
Q. When a primary amine reacts with chloroform in ethanolic solution of KOH, then the product is
- an isocyanide
- an aldehyde
- a cyanide
- an alcohol
Q. Identify (X), (Y) and (Z) in the given reaction
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1156478/original_3.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1156478/original_3.png)
- X=HCHO Y=CH3CHO Z=dil.KOH
- X=CH3CHO Y=CH3CHO Z=dil.NaOH
- X=CH3CH2OH Y=HCHO Z=H2SO4
- X=CH3CH2CHO Y=HCHO Z=dry ether
Q. Arrange the reactivity of given four compounds in decreasing order for nucleophilic addition reaction.
(1) Amide (2) Ester (3) Aldehyde (4) Ketone
(1) Amide (2) Ester (3) Aldehyde (4) Ketone
- 1>2>3>4
- 3>4>2>1
- 4>3>2>1
- 3>4>1>2
Q. CrO2Cl2 is formed while testing:
- NO−3
- Cl−
- Cr3+
- Fe3+
Q. AnilineCHCl3/KOH−−−−−−−−→ΔXi. LiAlH4−−−−−→ii. H2OY
(Y) is:
(Y) is:
- Ph−NH−CH3
- Ph−CH2−NH2
- Ph−NH−CHO
- Ph−⊕N≡⊖C
Q. If 1 stands for true and 0 stands for false, then choose the correct code for the following statement:
SO2 turns acidified K2Cr2O7 solution into a colorless solution.
SO2 turns acidified K2Cr2O7 solution into a colorless solution.
Q. Write the reaction showing the major and minor products when chlorobenzene is reacted with CH3Cl and CH3CoCl in present of AlCl3.