Distinguishing Test of Terminal and Non Terminal Alkynes
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- Benzene
- Ethane
- Cyclohexane
- Methylbenzene
- Gattermann–Koch reaction
- Friedel craft reaction
- Rosenmund reaction
- Stephen reaction
- Silver acetylene
- Silver acetate
- Disilver acetylide.
- Silver mirror
- Br2, CCl4
- H2, Pd, BaSO4
- [Ag(NH3)2]NO3
- Dilute H2SO4, HgSO4
- CH3−CH2−CH2−CH=CH−CH3
- CH3−CH=CH−C≡CH
- CH3−CH2−CH=CH−CH2−CH3
- CH2=CH−CH2−CH3
i.e. CH3−C≡C−CH3R⟶trans-alkene:
- H2/Pd/CaCO3
- Na/NH3(l)
- Na/dry ether
- Cr2O3/Al2O3
Reason (R): Lithium being very small in size polarises large carbonate ions leading to the formation of more stable Li2O and CO2.
- A is not correct but R is correct.
- Both A and R are correct and R is the correct explanation of A.
- Both A and R are not correct.
- Both A and R are correct and R is not the correct explanation of A.
Give the products formed when:
When Ammoniacal Cuprous chloride is added to Ethyne_______.
(i) CH3−C≡C−CH3
(ii) CH3−CH2−CH2−CH3
(iii) CH3−CH2−C≡CH
(iv) CH3−CH=CH2
- Ammonical silver nitrate
- Bromine in carbon tetrachloride
- Bromine in acetic acid
- Alkaline KMnO4
What compound of sulfur is obtained when concentrated oxidizes ?
- Methylacetylene is an example of terminal alkyne
- Terminal alkynes are more acidic when compared with alkenes
- Terminal alkynes are not as acidic as alkanes
- These have a replacable acidic hydrogen atom
Where, A and B are geometrical isomers (R−CH=CH−R).
Choose the correct option from the following:
- A is trans, B is cis
- A and B both are cis
- A and B both are trans
- A is cis, B is trans
CH3CH=CHCH3+O3Zn−−→H2OB
The compound B is:
- CH3COCH3
- CH3CH2COCH3
- CH3CHO
- CH3CH2CHO
Will CCl4 give white precipitate of AgCl on heating it with silver nitrate? Give reason for your answer.
- T is soluble in hot aqueous NaOH
- U is optically active
- Molecular formula of W is C10H18O4
- V gives effervescence on treatment with aqueous NaHCO3.
- CH3−CH=CH−C≡CH
- CH3−CH2−CH2−CH=CH−CH3
- CH3−CH2−CH=CH−CH2−CH3
- CH2=CH−CH2−CH3
(i)CH2Cl2(ii)CHCl3(iii)CCl4
- Ammoniacal cuprous chloride
- Conc. H2SO4
- Bromine water
- Alkaline KMnO4
- An optical active compound
- An optical inactive compound
- A racemic mixture
- A diastereomeric mixture
- But-1-yne
- Hex-1-yne
- Hex-2-yne
- (a) and (b) above.
_______ salt of sodium contains 10 molecules of water of crystallization.
- [Cu(NH3)2]+OH−
- Br2 in CCl4
- Alkaline KMnO4
- AlCl3
A tertiary alcohol H upon acid catalyzed dehydration gives a product I. Ozonolysis of I leads to compounds J and K.Compound J upon reaction with KOH gives benzyl alcohol and a compound L, whereas K on reaction with KOH gives only M.
The structures of compounds J, K and L respectively, are
- PhCOCH3, PhCH2COCH3 and PhCH2COO−K+
- PhCHO, PhCH2CHO and PhCOO−K+
- PhCOCH3, PhCH2CHO and CH3COO−K+
- PhCHO, PhCOCH3 and PhCOO−K+
i. Identify 'A' and 'B' and write their structural formulas.
ii. Name the type of isomerism involved.
iii. Give the IUPAC name of 'A' and 'B'.
- 2-Pentyne
- Hex-3-yne
- Hex-2-yne
- 1-Pentyne
When treated with ammoniacal cuprous chloride, which one among the following forms copper derivative
C2H6
C2H4
C6H6
C2H2
- 1-Butyne
- 4-Octyne
- 2-Hexyne
- All of the above.
Write the free radical mechanism for the polymerisation of ethene.