Entropy Change in Isobaric Process
Trending Questions
Q. What is the entropy change in 2 mol N2 when its temperature is taken from 400 K to 800 K, at constant pressure?
- 30 J/K
- 60 J/K
- 40 J/K
- 20 J/K
Q. Calculate the change in entropy of 1 mole of ideal gass, when temperature is lower down to 1/8 of initial temperature at constant volume is ?
- −3Cpln2
- −3Cpln2
- −3Cvln2
- 3Cvln2
Q. Find out the change in entropy ΔS in J K−1 when 4 mol of Helium gas is isobarically heated from 250 K to 350 K.
Assume Cp, m=5.19 kJ mol−1 K−1
Assume Cp, m=5.19 kJ mol−1 K−1
- 4812
- 3950
- 6989
- 7050
Q.
Which of the following is the correct expression of ΔS for an isobaric process?
None of these
Q.
Which of the following is the correct expression of ΔS for an isobaric process?
ΔS=nCPln T2T1+nR ln V2V1
ΔS=nCp lnT2T1
ΔS=nCp lnT1T2
None of these
Q.
Which of the following is the correct expression of ΔS for an isobaric process?
ΔS=nCPln T2T1+nR ln V2V1
ΔS=nCp lnT2T1
ΔS=nCp lnT1T2
None of these
Q. Find out the change in entropy ΔS in J K−1 when 4 mol of Helium gas is isobarically heated from 250 K to 350 K.
Assume Cp, m=5.19 kJ mol−1 K−1
Assume Cp, m=5.19 kJ mol−1 K−1
- 4812
- 3950
- 6989
- 7050
Q. Assertion :C+12O2⟶CO;ΔH=−26.0kcal
CO2+12O2⟶CO2;ΔH=−68.3kcal
C+O2⟶CO2;ΔH=−94.3kcal Reason: This is an experimental proof of Hess's law.
CO2+12O2⟶CO2;ΔH=−68.3kcal
C+O2⟶CO2;ΔH=−94.3kcal Reason: This is an experimental proof of Hess's law.
Read the above assertion and reason and choose teh correct option regarding it.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct