Entropy of Phase Change
Trending Questions
Q. The entropy change involved in the conversion of 1 mole of liquid water at 373 K to vapour will be:
Given: △Hvap=2.257 kJ/g
Given: △Hvap=2.257 kJ/g
- 150 JK−1mol−1
- 130.6 JK−1mol−1
- 118.5 JK−1mol−1
- 108.9 JK−1mol−1
Q.
The standard molar entropy of H2O (1) is 70 JK−1 mol−1. Will the standard molar entropy of H2O(s) be more, or less than 70 JK−1 mol−1?
Q. Entropy change involved in conversion of one mole of liquid water at 373 K to vapour at the same temperature (latent heat of vaporisation of water =2.257 kJg−1).
- 30.7 JK−1mol−1
- 60.3 JK−1mol−1
- 9.8 JK−1mol−1
- 108.9 JK−1mol−1
Q. The free energy and entropy change in kJ per mole when liquid water boils at atmospheric pressure are respectively (latent heat of water = 2.0723 kJ g−1)
- 0, 0
- 0.1, 0.1
- 0.1, 0
- 0, 0.1
Q. The enthalpy of vaporization of water at 100oC is 40.63 kJ mol−1. It's entropy change for the vaporization would be :
- 406.3 J K−1 mol−1
- 108.9 J K−1 mol−1
- 108.9 kJ K−1 mol−1
- 4063 kJ K−1 mol−1
Q. If △Hvaporisation of substance X(l) (molar mass : 30 g/mol) is 300 J/g at it's boiling point 300 K, then molar entropy change for reversible condensation process is
- None of these
- 30J/molK−1
- −60 J/molK−1
- −30 J/molK−1
Q. Change in entropy (in J/K) for freezing of 10 g of H2O(l) (enthalpy of fusion is 80cal/g) at 0∘ C and 1 atm is:
(Given: 1 cal=4.2 J, Round the answer upto one decimal point)
(Given: 1 cal=4.2 J, Round the answer upto one decimal point)
- 24.6 J/K
- 12.3 J/K
- 18.5 J/K
- 9.2 J/K
Q.
Does Entropy increase with volume?
Q. Predict in how many of the following processes entropy change of the system is positive .
(i) CaCO3(s)→CaO(s)+CO2(g)
(ii) N2(g)+3H2(g)→2NH3(g)
(iii) HCl(g)+NH3(g)→NH4Cl(s)
(iv) 2SO2(g)+O2(g)→2SO3(g)
(v) Cooling of N2(g) from 20oC to −50oC
(i) CaCO3(s)→CaO(s)+CO2(g)
(ii) N2(g)+3H2(g)→2NH3(g)
(iii) HCl(g)+NH3(g)→NH4Cl(s)
(iv) 2SO2(g)+O2(g)→2SO3(g)
(v) Cooling of N2(g) from 20oC to −50oC
- 2
- In all the processess
- 3
- 1
Q. Calculate the change in entropy when 1 mol of solid iodine at a temperature of 360 K is heated at constant pressure to produce liquid iodine at a temperature of 410 K. The constant pressure molar heat capacity of solid iodine is 54.44 J K−1 mol−1 and liquid iodine is 80.67 J K−1 mol−1.
The melting point of iodine is 387 K and molar enthalpy of fusion of iodine is 7.87 kJ/mol.
The melting point of iodine is 387 K and molar enthalpy of fusion of iodine is 7.87 kJ/mol.
- 8.6 JK−1 mol−1
- 28.9 JK−1 mol−1
- 20.3 JK−1 mol−1
- 11.7 JK−1 mol−1
Q. At 373 K, steam and water are in equilibrium and △vapH=40.98 kJ mol−1. What will be entropy change for conversion of water into steam?
H2O(l)→H2O(g)
H2O(l)→H2O(g)
- 109.8 J K−1 mol−1
- 31 J K−1 mol−1
- 21.98 J K−1 mol−1
- 326 J K−1 mol−1
Q. If latent heat of fusion of ice is 80 cal per mole at 0 ∘C, calculate molal depression constant for water.
- 0.1863 K kg mol−1
- 1.863 K kg mol−1
- 186.3 K kg mol−1
- 18.63 K kg mol−1
Q.
The entropy values in JK−1 mol−1 of H2(g)=130.6, Cl2(g)=233 and HCl(g)=186.7 at 298K and 1 atm pressure. Then entropy change for the reaction
H2(g)+Cl2(g)→2HCl(g) is:
- +540.3
- +727.3
- −166.9
- +9.8
Q. Predict in how many of the following processes entropy change of the system is positive .
(i) CaCO3(s)→CaO(s)+CO2(g)
(ii) N2(g)+3H2(g)→2NH3(g)
(iii) HCl(g)+NH3(g)→NH4Cl(s)
(iv) 2SO2(g)+O2(g)→2SO3(g)
(v) Cooling of N2(g) from 20oC to −50oC
(i) CaCO3(s)→CaO(s)+CO2(g)
(ii) N2(g)+3H2(g)→2NH3(g)
(iii) HCl(g)+NH3(g)→NH4Cl(s)
(iv) 2SO2(g)+O2(g)→2SO3(g)
(v) Cooling of N2(g) from 20oC to −50oC
- In all the processess
- 3
- 1
- 2
Q. Calculate the enthalpy of vaporisation (in kJ/mol) for ethanol. Given, entropy change for the process is 109 J K−1 mol−1 and boiling point of ethanol is 78.5 oC.
Q. Entropy change involved in conversion of one mole of liquid water at 373 K to vapour at the same temperature (latent heat of vaporisation of water =2.257 kJg−1).
- 30.7 JK−1mol−1
- 60.3 JK−1mol−1
- 9.8 JK−1mol−1
- 108.9 JK−1mol−1
Q. At 0oC, if enthalpy of fusion of ice is 1365 kcal/mol, the molar entropy change for melting of ice at 0oC is?
Q. Enthalpy of fusion of water is 6.01kJ mol−1. The entropy change of 1 mole of ice at its melting point will be:
- 44 kJ mol−1
- 22 kJ mol−1
- 109 kJmol−1
- 11 kJ mol−1
Q. The enthalpy of vaporisation of liquid diethyl ether (C2H5)2O is 26 kJ mol−1 at its boiling point 35oC. Calculate △So for conversion of vapour to liquid (condensation) at 35oC.
- −84.41 J K−1 mol−1
- +84.41 J K−1 mol−1
- −48.41 J K−1 mol−1
- +48.41 J K−1 mol−1
Q. The enthalpy of vaporisation of liquid diethyl ether (C2H5)2O is 26 kJ mol−1 at its boiling point 35 oC. Calculate △So for conversion of vapour to liquid (condensation) at 35 oC.
- −84.41 J K−1 mol−1
- +84.41 J K−1 mol−1
- −48.41 J K−1 mol−1
- +48.41 J K−1 mol−1
Q. Ethanol boils at 78.4oC and the enthalpy of vaporisation of ethanol is 42.4 kJ mol−1 . What will be the entropy of vaporisation of ethanol:
- 101.5 JK−1 mol−1
- 150 JK−1 mol−1
- 120.66 JK−1 mol−1
- 135 JK−1 mol−1
Q. Calculate the entropy change when 1 mol of ice 0∘C is converted into water at 0∘C. The change in heat is 1436 cal per mol.
None of these
Q. Calculate the change in entropy for fusion of 1 mole of ice. The melting point of ice is 273 K and molar enthalpy of fusion for ice = 6.0 kJ mole−1
- △Sf =21.97 JK−1 mol−1
- △Sf =21.87 JK−1 mol−1
- △Sf =21.78 JK−1 mol−1
- △Sf =21.79 JK−1 mol−1
Q. If enthalpy of vaporisation of water is 186.5kJ/mol, the entropy of its vaporisation will be:
- 1.5
- 1.0
- 2.0
- 0.5
Q. Entropy change involved in conversion of one mole of liquid water at 373 K to vapour at the same temperature (latent heat of vaporisation of water =2.257 kJg−1).
- 30.7 JK−1mol−1
- 60.3 JK−1mol−1
- 9.8 JK−1mol−1
- 108.9 JK−1mol−1
Q. At 40oC, the vapour pressure in torr of methanol and ethanol solution is P=119x+135. Here, x is the mole fraction of methanol. Hence, _______________ .
- vapour pressure of equimolar mixture of each is 127mm
- mixture is completely immiscible
- vapour pressure of pure ethanol is 135 torr
- vapour pressure of pure methanol is 119 torr
Q. For a liquid, enthalpy of fusion is 1.435 kcal mol−1 and molar entropy change is 5.26 cal mol−1K−1. The melting point of the liquid is:
- −273oC
- 173oK
- 100oC
- 0oC
Q.
During which of the following processes, does Entropy decrease ?
$ \left(a\right)$ Freezing of water to ice at $ {0}^{°} c$
$ \left(b\right)$ Freezing of water to ice at $ -{10}^{° } C$
$ \left(c\right)$
$ \left(d\right)$ Adsorption of $ CO\left(g\right)$ on lead surface.
$ \left(e\right)$ Dissolution of $ NaCl$ in water
Q.
Calculate entropy change for vaporization of 1 mole of liquid water to steam at 100∘C if ΔHv=40.8 kJ mol−1.
ΔSv=107.38 JK−1 mol−1
ΔSv=109.48 JK−1 mol−1
ΔSv=109.38 JK−1 mol−1
ΔSv=107.38 JK−1 mol−1
Q. Calculate the change in entropy for fusion of 1 mole of ice. The melting point of ice is 273 K and molar enthalpy of fusion for ice = 6.0 kJ mole−1
- △Sf =21.97 JK−1 mol−1
- △Sf =21.87 JK−1 mol−1
- △Sf =21.78 JK−1 mol−1
- △Sf =21.79 JK−1 mol−1