Heisenberg's Uncertainty Principle
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h=6.6×10−34 Js, mass of electron, em=9.1×10−31 kg
- 5.10×10−3 m
- 1.92×10−3 m
- 3.84×10−3 m
- 1.52×10−3 m
- 1.12×10−10
- 2.11×10−8
- 2.11×10−10
- 1.12×10−8
An electron has a speed of 500 m/s with an uncertainty of 0.02% What is the uncertainty in position?
- 1.54 X 1015 s-1
- 1.03 X 1015 s-1
- 3.08 X 1015 s-1
- 2 X 1015 s-1
- 1.92 cm
- 7.68 cm
- 5.76 cm
- 3.84 cm
(Given : Mass of electron =9.1×10−31 kg, Planck's constant h=6.63×10−34Js)
- zero
For the 1s orbital of the Hydrogen atom, the radial wave function is given as:
R(r)=1√π(1a0)32e−ra0 (Where a0=0.529 ∘A)
The ratio of radial probability density of finding an electron at r=a0 to the radial probability density of finding an electron at the nucleus is given as (x.e−y).
Calculate the value of (x+y).
- 2√3
- 3√2
- √3
- 2
(h=6.6×10−34kgm2s−1)
- 5.809×10−24m s−1
- 3.5×10−24m s−1
- 9.077×10−24m s−1
- 1.908×10−24m s−1
- 2.05 ms−1
- 1.50 ms−1
- 1.20 ms−1
- 0.20 ms−1
- 1.32×10−30 m/s
- 2.63×10−29 m/s
- 0.55×10−30 m/s
- 4.55×10−29 m/s
Explain de Broglie wave theory
- 5.76×10−3 m
- 1.92×10−2 m
- 3.84×10−3 m
- 19.2×10−4 m
- 1.76×10−35 J
- 1.76×10−34 J
- 1.76×10−33 J
- 1.76×10−38 J
The expression:∆x×∆p(>or=)h/4π or h/2π
Which is correct?
Question 10
Which of the following is responsible to rule out the existence of definite paths or trajectories of electrons ?
(a) Pauli's exclusion principle
(b) Heisenberg's uncertainty principle
(c) Hund's rule of maximum multiplicity
(d) Aufbau principle
If the position of the electron is measured within an accuracy of + 0.002 nm, calculate the uncertainty in the momentum of the electron. Suppose the momentum of the electron is h/4πm × 0.05 nm, is there any problem in defining this value.
In a given atom no two electrons can have the same values for all the four quantum numbers. This is called
Pauli's exclusion principle
Uncertainty principle
Hund's rule
Aufbau's principle
- 5.2×10−7 m
- 5.2×10−6 m
- 5.2×10−9 m
- 5.2×10−8 m
How to determine the exact position and momentum of an electron?
(h=6.6×10−34 kg m2 s−1, Mass of electron=9.1×10−31 kg)
- 2.30×10−3m
- 1.52×10−4m
- 5.1×10−3m
- 3.84×10−3m
- Zeeman effect
- Stark effect
- Heisenberg's Uncertainity Principle
- Line spectrum of hydrogen atom
- 3.35×10−3 ms−1
- 5.8×10−4 ms−1
- 4×10−5 ms−1
- 4×10−6 ms−1
According to Heinsbergs the principal, the product of uncertainty is position and velocity for an electron of mass -31
9.1×10
-3 -5 -5 -6
(a) 2.8×10 (b) 3.8×10 (c)5.8×10 (d)6.8×10
How to solve it
The wave mechanical model of an atom is based upon
de-Broglie concept of dual character of matter
Heisenberg’s uncertainty principle
Schrodinger’s wave equation
All the three above
5.2×10−8 m
5.2×10−7 m
5.2×10−6 m
5.2×10−9 m
According to the Schrodinger a particle is equivalent to:
a wave
a particle only
both of them
none of them