Hess' Law
Trending Questions
- (CH3)3C–O–C2H5
- CH3CH2CH2–O–CH2CH2CH3
- Ph–O–CH2CH3
- CH3CH=CH–O–CH=CH2
The following reaction is an example of
Addition reaction
Substitution reaction
Combustion reaction
Displacement reaction
If at 298 K the bond energies of C - H, C - C, C=C and H - H bonds are respectively 414, 347, 615 and 435 kJ mol−1, the value of enthalpy change for the reaction
CH2=CH2(g)+H2(g)→CH3−CH3 is:
-250 kJ
+125 kJ
-125 kJ
+250 kJ
Enthalpy of sublimation of K=89 kJmol−1
Enthalpy of dissociation of Cl2=244 kJmol−1
Ionisation energy of K=425 kJmol−1
Electron gain enthalpy of Cl=−355 kJmol−1
Enthalpy of formation of KCl=−438 kJmol−1
- 719 kJmol−1
- −719 kJmol−1
- −832 kJmol−1
- 832 kJmol−1
- C2H5Br
- CH3Br
- CH2=CH−Br
- CH2=CH−CH2−Br
Define the order of reaction?
Use the following data to calculate ΔlatticH⊖ for NaBr. ΔsubH⊖ for sodium metal = 108.4 kJ mol−1, ionisation enthalpy of sodium = 496 kJ mol−1, electron gain enthalpy of bromine = -325 kJ mol−1, bond dissociation enthalpy of bromine = 192 kJ mol−1, ΔfH⊖ for NaBr(s) = -360. 1 kJ mol−1
A chemical reaction was carried out at 300K and 280K. The rate conatants were found to be K1 and K2 respectively. Then
1)K2 = 4 K1
2)K2 =2 K1
3)K2 = 0.5 K1
4)K2 = 0.25 K1
This reaction was studied at and the following data was obtained.
and are the initial concentrations and is the initial reaction rate. The overall order of the reaction is _________. (Round off to the Nearest Integer).
- -92.2 kJ/mol
- -46.1 kJ/mol
- 46.1 kJ/mol
- -92.2 kJ/mol
- −535.5 kJ/mol
- −238 kJ/mol
- −357 kJ/mol
- −119 kJ/mol
The enthalpies of formation of Al2O3 and Cr2O3 are −1569 KJ and −1134 KJ respectively. ΔH for the reaction
2Al + Cr2O3 → 2Cr + Al2O3 is
- −2730 KJ
- −462 KJ
- −1365 KJ
- +2730 KJ
Calculate the standard internal energy change for the reaction at 25⁰C:-
C2H4(g) + 3O2(g)----------à 2CO2 (g) + 2H2O (l) DH for C2H4 (g) = 52.30 kJ/mole,
CO2 = - 393.5 kJ/mole H2O = - 286 kJ/mole R = 8.314 J/K/mole.- 4
- 6
- 7
- 5
- The low ionisation potential of Na
- The high electron affinity of Cl
- The Lattice energy
- The low ΔHvap of Na(s)
Enthalpy is an extensive property. In general, if enthalpy of an overall reaction A → B along one route is ΔrH and ΔrH and ΔrH1, ΔrH2, ΔrH3 ⋯ represent enthalpies of intermediate reactions leading to product B. What will be the relation between ΔrH overall reaction and ΔrH1, ΔrH2 ⋯ etc for intermediate reactions.
- Lavoisier and Laplace law
- Hess's law
- Joule's law
- Le–chatelier's principle
The molar entropies of HI(g), H(g) and I(g) at 298K are 206.5, 114.6, and 180.7 J mole−1 K−1 respectively. Using the Δ G0 given below, Calculate the bond energy of HI.
H(g) → H(g) + I(g); Δ G0 = 271.8 kJ
282.4 kj/mole
298.3 kJ/mole
100 kJ/mole
32.17kJ/mole
Which Reaction is Exothermic?
How much energy will mass of wood yield on complete combustion if its calorific value were ?
- Change in enthalpy during the reaction
- Equilibrium constant
- Infulence of pressure on volume
- Rate of reaction
- Law of constant heat summation
- Law of constant heat of enthalpy
- Law of constant heat capacity
- None of these
- Law of constant heat summation
- Law of constant heat of enthalpy
- None of these
- Law of constant heat capacity
- to find out electron affinity of non-metal atom
- both (a) and (b) above.
- to find out lattice energy of the ionic compounds
- for the preparation of ammonia in industries
- The low ionisation potential of Na
- The high electron affinity of Cl
- The low ΔHvap of Na(s)
- The Lattice energy