Hybridisation
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- Be2H4
- C3H4
- Al2Me6
- B2H6
What do you mean by Hybridization?
In the organic compound CH2=CH−CH2−CH2–C≡CH, the pair of hydridised orbitals involved in the formation of: C2−C3 bond is:
(a) sp−sp2 (b) sp−sp3 (c) sp2−sp3 (d) sp3−sp3
- sp3 and sp3
- sp3 and sp2
- sp2 and sp3
- sp2 and sp2
NF3, NO−3, BF3, H3O+
- [NF3, NO−3] and [BF3, H3O+]
- [NF3, H3O+] and [NO−3, BF3]
- None of the above
- [NF3, H3O+] and [NF3, BF3]
- Octahedral
- Trigonal bipyramidal
- Pentagonal planar
- Square pyramidal
Is there any change in the hybridisation of B and N atoms as a result of the following reaction?
BF3+NH3→F3B.NH3
- Bent
- Trigonal planar
- Linear
- Trigonal bipyramidal
- AsH3
- H2S
- H2Se
- All of the above
- two
- three
- four
- five
Here a, b, c are monodentate ligands
- 2 geometrical isomers.
- 1 enantiomeric pair.
- no optically active geometrical isomer
- All of the above.
CO2−3I;XeF4II; I−3III; NCl3IV; BeCl2(g)V
- II< III< IV< I< V
- II< IV< III< V< I
- III< II< I< V< IV
- II< IV< III< I< V
- SF4
- BF−4
- NH+4
- CH4
Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code.
Column~I Column~II (Complex ion) (Hybridisation, number of unpaired electrons)A. [Cr(H2O)6]3+1. dsp2, 1B. [Co(CN)4]2−2. sp3d2, 5C. [Ni(NH3)6]2+1. d2sp3, 3D. [MnF6]4−2. sp3d2, 2
Codes
ABCD(a)3142(b)4321(c)3241(d)4123
(i) Ethyl iodide undergoes SN2 reaction faster than ethylbromide.
(ii) (±)2 - Butanol is optically inactive.
(iii) C - X bond length in halobenzene is smaller than C - X bond length in CH3−X.
- The molecule is planar
- The shape of the molecule is bent
- O-atom is sp3-hybridised.
- The molecule is non-planar.
- It originates from the mixing of one s and two p orbitals
- BH3 and NH3 show this hybridisation
- All the hybrid orbitals remain in one plane
- Carbon containing one double bond exhibits this type of hybridisation
- Octahedral
- Tetrahedral
- See-saw
- Square planar
- SF4
- I−3
- SbCl2−5
- PCl5
- Multiple bonds are always shorter than the corresponding single bonds
- The electron deficient molecules can act as Lewis acids
- Canonical structures have no real existence
- Every AB6 type molecule has square pyramidal structure
- SO2
- BeCl2
- BF3
- CH4
- sp3d
- (a) and (b) above.
- sp2
- sp3
Find the sum of the interior angles of a nonagon.
- sp and sp2
- sp2 and sp3
- sp and sp3
- only sp3
- 3
- 4
- 5
- 6
- ClF3
- NCl3
- BCl3
- NH3
- sp2
- sp
- sp3
- All of the above have same bond angle.