Ion Electron Method
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How would you balance:
How would you balance the following equation:
H2SO4 + 2NaOH→Na2SO4 + 2H2O
When 1L of 0.1M sulphuric acid solution is allowed to react with 1L of 0.1M sodium hydroxide solution, the amount of sodium sulfate formed and its molarity in the solution obtained is
- 7.10 g
- 3.55 g
- 0.1 mol L−1
- 0.025 mol L−1
Balance the following redox reactions by ion-electron method:
MnO−4(aq)+I−(aq)→MnO2(s)+I2(s) (in basic medium)
MnO−4(aq)+SO2(g)→Mn2+(aq)+(aq)HSO−4(aq) (in acidic solution)
H2O2(aq)+Fe2+(aq)→Fe3+(aq)+H2O(l) (in acidic solution)
Cr2O2−7+SO2(g)→Cr3+(aq)+SO2−4 (aq) (in acidic solution)
How would you balance the following equation:
Which of the following expression correctly represents the equivalent conductivity at infinite dilution of Al2(SO4)3?
Given that λ∘Al3+ and λ∘SO2−4 are the equivalent conductivities at infinite dilution of the respective ions.
- 2λ∘Al3++3λ∘SO2−4
- λ∘Al3++λ∘SO2−4
- (λ∘Al3++3λ∘SO2−4)×6
- 13λ∘Al3++12λ∘SO2−4
Balance the following equations in basic medium by ion-electron method and oxidation number methods and identify the oxidising agent and the reducing agent.
P4(s)+OH−(aq)⟶PH3(g)+HPO−2(aq)
N2H4(I)+CIO−3(aq)⟶NO(g)+CI−(g)
Cl2O7(g)+H2O2(aq)⟶CIO−2(aq)+O2(g)+H+(aq)
3Cl2+6NaOH→5NaCl+NaClO3+3H2O
- 42.6
- 35.5
- 59.1
- 71
Br2+OH−→BrO−3+Br−+H2O
is balanced by ion electron method. Choose the correct statement(s) regarding stoichiometric ratios nanb :
Here a, b represents different species in the reaction.
- nBr2nBrO−3=32
- nBr2nBrO−3=3
- nOH−nH2O=2
- nOH−nH2O=3
Which of the following is not a balanced equation?
ClO−+CrO−2→Cl−+CrO2−4
When balanced in a basic medium by oxidation number method, the ratio of stoichiometric coefficient of OH− and H2O(nOH−nH2O) will be:
- 1:1
- 2:1
- 1:2
- 1:4
Give the balanced equation for the action of heat on the following compound:
Silver oxide.
MnO−4+C2O2−4+H+⟶Mn2++CO2+H2O
- 4
- 2
- 3
- 5
Calculate the volume of 0.1 M NaOH solution required to neutralize the acid formed by dissolving 1.1 g of P4O6 in H2O.
KMnO4+H2SO4+HCl→K2SO4+MnSO4+Cl2+H2O
- 2KMnO4+10HCl+2H2SO4→5Cl2+2MnSO4+8H2O
- 2KMnO4+10HCl+3H2SO4→5Cl2+2MnSO4+8H2O
- 2KMnO4+10HCl+H2SO4→5Cl2+2MnSO4+8H2O
- 2KMnO4+HCl+3H2SO4→5Cl2+2MnSO4+8H2O
FeS2+O2→Fe2O3+SO2
PbS+H2O2→PbSO4+H2O
- 2PbS+4H2O2→2PbSO4+4H2O
- PbS+4H2O2→PbSO4+4H2O
- PbS+2H2O2→PbSO4+2H2O
- 2PbS+2H2O2→2PbSO4+4H2O
KMnO4 acts as an oxidizing agent in:
- acidic medium only
- neutral and acidic media
- neutral and alkaline media
- neutral, acidic and alkaline media
Which reaction does not represent auto redox or disproportionation?
H2O2(aq)+Cl2O7(aq)→ClO−2(aq)+O2(g)
Moles of OH− and H2O respectively present in a balanced equation in a basic medium are x and y. Calculate the value of x+y:
The equivalent weight of , when it reacts with to give is _______.
Infinite
In an electrolysis experiment current was passed for 5 hours through two cells connected in series. The first cell contains a solution of gold and the second contains copper sulphate solution. 9.85 g of gold was deposited in the first cell. If the oxidation number of gold is +3, find the amount of copper deposited on the cathode of the second cell.
(At.wt. of Au = 197 and At.wt of Cu = 63.5)
4.76 g
2.34
8.9 g
6.6 g
What product is formed on disproportionation of ?
What happens when carbon dioxide reacts with sodium oxide?
Cu2O+H++NO−3→Cu2++NO+H2O
- 3Cu2O+14H++2NO−3→6Cu2++2NO+7H2O
- 6Cu2O+14H++NO−3→6Cu2++2NO+7H2O
- 3Cu2O+14H++4NO−3→6Cu2++4NO+7H2O
- None
KMnO4+H2SO4+H2O2→K2SO4+MnSO4+O2+H2O
- 0.12 L
- 0.56 L
- 1.12 L
- 0.03 L