Le Chatelier's Principle for Del N Equals to 0
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For the reaction CO(g)+H2O(g)⇌CO2(g)+H2(g) at a given temperature, the equilibrium amount of CO2(g) can be increased by
Adding an inert gas
Adding a suitable catalyst
Decreasing the volume of the container
Increasing the amount of CO (g)
2A + 3B ⇌ 3C + 2D
- Forward reaction is favoured
- Backward reaction is favoured
- No effect
- It will stop the reaction
Regarding the rate of a reversible reaction, the correct explanation of the effect
of catalyst is
It provides a new reaction path of low activation energy
It decreases the velocity of backward reaction
It increases the kinetic energy of reacting molecules
It displaces the equilibrium state on right side
The effect of increasing the pressure on the equilibrium
2A(g)+3B(g) ⇌ 3A(g)+2B(g) is
- Backward reaction is favoured
- None of the above
- Forward reaction is favoured
- No effect
A2(g)+2B(g)⇌C(g)+Q kJ
would be higher at:
- Low temperature and high pressure
- High temperature and high pressure
- Low temperature and low pressure
- High temperature and low pressure
C2H4(g)+H2(g)⇌C2H6(g); △Ho=−136.8 kJ mol−1
carried out in a vessel, the equilibrium concentration of C2H4 can be increased by:
- Increasing the temperature
- Decreasing the pressure
- Removing some H2
- Adding some C2H6
- 2NO(g)+O2(g)⇌2NO2(g)
- H2(g)+I2(g)⇌2HI(g)
- N2(g)+3H2(g)⇌2NH3(g)
- N2O4(g)⇌2NO2(g)
Which of the following reactions will get affected by increasing the pressure?
Also, mention whether change will cause the reaction to go into forward or backward direction.
(i) COCl2(g)↔CO(g)+Cl2(g)
(ii) CH4(g)+2S2(g)↔CS2(g)+2H2S(g)
(iii) CO2(g)+C(s)↔2CO(g)
(iv) 2H2(g)+CO(g)↔CH3OH(g)
(v) CaCO3(s)↔CaO(s)+CO2(g)
(vi) 4NH3(g)+5O2(g)↔4NO(g)+6H2O(g)
- Amount of solid to decrease
- Amount of liquid to decrease
- Temperature to rise
- Temperature to fall