Ostwald Dilution Law Mathematical Interpretation
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At 25∘C, the dissociation constant of a base BOH is 1.0 × 10−12. The
concentration of Hydroxyl ions in 0.01 M aqueous solution of the base
would be
2.0 x 10-6 mol L-1
1.0 x 10-5 mol L-1
1.0 x 10-6 mol L-1
1.0 x 10-7 mol L-1
- 2
- 2.3
- 1.7
- 0.3
A monoprotic acid in 1.00 M solution is 0.01% ionised. The dissociation constant of this acid is
1 X 10-8
1 X 10-4
1 X 10-6
1 X 10-5
It has been found that the pH of a 0.01M solution of an organic acid is 4.15. Calculate the concentration of the anion, the ionization constant of the acid and its pKa.
(Note: Degree of dissociation (α) of weak acid and weak base is << 1; degree of hydrolysis of salt << 1; [H+] represents the concentration of H+ ions)
LIST -ILIST-IIP. 10 mL of 0.1 M NaOH +20 mL of1. The value of [H+] does not0.1 M acetic acid diluted to 60 mLchange on dilutionQ. 20 mL of 0.1 M NaOH +20 mL of2. The value of [H+] changes to half0.1 M acetic acid diluted to 80 mLof its initial value on dilutionR. 20 mL of 0.1 M HCl + 20 mL of 0.13. The value of [H+] changes to twoM ammonia solution diluted to 80 mLtimes of its initial value on dilutionS. 10 mL saturated solution of Ni(OH)24. The value of [H+] changes to 1√2in equilibrium with excess solid Ni(OH)2times of its initial value on dilutionis diluted to 20 mL (solid Ni(OH)2is stillpresent after dilution).5. The value of [H+] changes to √2times of its initial value on dilution
Match each process given in LIST -I with one or more effect(s) in LIST -II. The correct option is
- P→4;Q→3;R→2;S→3
- P→1;Q→4;R→5;S→3
- P→4;Q→2;R→3;S→1
- P→1;Q→5;R→4;S→1
- 1.4×10−4
- 1.4×10−5
- 3.7×10−4
- 2.8×10−4
What Is the pH Of Nucleic Acid?
Given : Ka for HA=10−6 and Kb for BOH=10−6
- 5, 1%
- 7, 10%
- 9, 0.01%
- 7, 0.01%
0.1 mole of HCl is added to 2 litres of buffer solution. The decreases in pH of that buffer by 0.5. Then the buffer capacity is
0.5
0.2
0.1
2
[Ka(HA)=2×10−5;Ka(HB)=4×10−5]
log(2.44)=0.387
√6=2.44
- 2.61
- 4.56
- 3.49
- 1.02
pH of two solutions :
I. 50 ml of 0.2 M~HCl + 50 ml of 0.2 M HA (Ka=1.0×10−5) and
II. 50 ml of 0.2 M HCl + 50 ml of 0.2 M NaA will be respectively
3 and 1
0.70 and 2.85
1 and 2.85
1 and 3
- 2×10−6 mole L−1
- 2×10−5 mole L−1
- 3×10−6 mole L−1
- 3×10−5 mole L−1
A monoprotic acid in 1.00 M solution is 0.01% ionised. The dissociation constant of this acid is
1 × 10−8
1 × 10−4
1 × 10−6
1 × 10−5
The dissociation constant of two acids HA1 and HA2 are 3.14 × 10−4 and 1.96 × 10−5 respectively. The relative strength of the acids will be approximately
1:4
4:1
1:16
16:1
- N/5
- N/10
- N/20
- N/40
- N7.5
- N15
- N5
- N8
- 2.8×10−3
- 9×10−5
- 9×10−4
- 81×10−4
At 25∘C, the dissociation constant of a base BOH is 1.0 × 10−12. The
concentration of Hydroxyl ions in 0.01 M aqueous solution of the base
would be
2.0 × 10−6molL−1
1.0 × 10−5molL−1
1.0 × 10−6molL−1
1.0 × 10−7molL−1
- 200 mL
- 600 mL
- 400 mL
- 800 mL
- 9
- 5
- 24
- 16
- basic
- none of these
- neutral
- acidic
At 25∘C, the dissociation constant of a base BOH is 1.0 × 10−12. The
concentration of Hydroxyl ions in 0.01 M aqueous solution of the base
would be
2.0 × 10−6molL−1
1.0 × 10−5molL−1
1.0 × 10−6molL−1
1.0 × 10−7molL−1
The dissociation constant of two acids HA1 and HA2 are 3.14 × 10−4 and 1.96 × 10−5 respectively. The relative strength of the acids will be approximately
1:4
4:1
1:16
16:1
- 3:5
- 5:3
- 100:1
- 1:100
- 1 : 4
- 4 : 1
- 1 : 16
- 16 : 1
[Dissociation constant is 1 ×10−5]
- 10−5
- 10−4
- 10−3
- 10−2