Oxidation Number Method
Trending Questions
How many moles of is required to oxidise one mole of in an acidic medium.
- MnO−4+2Br−+H2O→MnO2+2BrO−3+2OH−
- 2MnO−4+Br−+H2O→2MnO2+BrO−3+2OH−
- MnO−4+Br−+H2O→2MnO2+BrO−3+2OH−
- 2MnO−4+Br−+H2O→MnO2+BrO−3+2OH−
- 40 %
- 5 %
- 50 %
- 25 %
Write the balanced chemical equations for the following reactions and identify the type of reaction in each case.
(d) ethene is burnt in the presence of oxygen to form carbon dioxide, and water and releases heat and light.
Balance the chemical equation
The equivalent weight of Mohr’s salt is
MnO−4+C2O2−4→Mn2++CO2
- 2
- 1
- 3
- 5
Balance the following equation by ion electron method
Na2S2O3+I2=Na2S4O6+NaI
Solid calcium carbonate is heated to produce solid calcium oxide and carbon dioxide gas is released
(a) Translate the following chemical change in the form of a chemical equation
(b) Make it informative
(c) Balance it if required
Assign oxidation numbers to the underlined elements in each of the following species:
NaH2PO4
NaHS––O4
H4P––2O7
K2Mn––––O4
CaO––2
NaB––H4
H2S––2O7
KAlS––O4)2.12H2O
Balance the reaction : and identify the Oxidizing and Reducing agents
reacts with ozone to form lead sulphate and oxygen. As per the balanced equation, molecules of ozone required for every molecule of are:
4
3
2
1
- HCHO
- CH2Cl2
- C6H12O6
- All of the above
How to calculate the equivalent weight of ferrous ammonium sulphate?
- Cr2O−27(aq)+3SO−23(aq)+H+(aq)→2Cr+3(aq)+3SO−24(aq)+4H2O(aq)
- Cr2O−27(aq)+3SO−23(aq)+8H+(aq)→2Cr+3(aq)+3SO−24(aq)+4H2O(aq)
- Cr2O−27(aq)+3SO−23(aq)+8H+(aq)→Cr+3(aq)+3SO−24(aq)+4H2O(aq)
- Cr2O−27(aq)+SO−23(aq)+8H+(aq)→2Cr+3(aq)+3SO−24(aq)+4H2O(aq)
Why is used in Contact Process?
- OF2<KO2<BaO2<O3
- BaO2<O3<OF2<KO2
- KO2<OF2<O3<BaO2
- BaO2<KO2<O3<OF2
An unbalanced chemical equation is called_________ equation.
- M
- M2
- M4
- 2M
Write the balanced chemical equations for the following reactions
Magnesium burns in carbon dioxide to form magnesium oxide and carbon.
- HNO3, NO, NH4Cl, N2
- NO, HNO3, NH4Cl, N2
- HNO3, NO, N2, NH4Cl
- HNO3, NH4Cl, NO, N2
(i) KMnO2+HCl→KCl+MnCl2+H2O+Cl2
(ii) NH3+O3→NO+H2O
Balance this reaction using the ion-electron method in the shortest way possible:
S4O2−6(aq)+Al(s)→H2S(aq)+Al3+(aq)
What will be the net balanced equation in an acidic medium (by oxidation number method).
- 2S4O2−6(aq)+6Al(s)+15H+→2H2S(aq)+6Al3+(aq)+6H2O(l)
- S4O2−6(aq)+6Al(s)+20H+→4H2S(aq)+6Al3+(aq)+6H2O(l)
- 3S4O2−6(aq)+6Al(s)+2H+→3H2S(aq)+6Al3+(aq)+6H2O(l)
- S4O2−6(aq)+5Al(s)+20H+→4H2S(aq)+5Al3+(aq)+4H2O(l)
List -I | List-II | ||
(a) | NaN3 | (1) | +5 |
(b) | N2H2 | (2) | +2 |
(c) | NO | (3) | −13 |
(d) | N2O5 | (4) | −1 |
- a→1, b→4, c→2, d→1
- a→4, b→3, c→2, d→1
- a→3, b→4, c→1, d→2
- a→3, b→4, c→2, d→1
Tl2O3(s)+NH2OH(aq)→TlOH(s)+N2(g)
- Tl2O3(s)+4NH2OH(aq)→2TlOH(s)+2N2(g)+5H2O
- Tl2O3(s)+2NH2OH(aq)→2TlOH(s)+N2(g)+5H2O
- Tl2O3(s)+2NH2OH(aq)→2TlOH(s)+N2(g)+5H2O
- 2Tl2O3(s)+4NH2OH(aq)→4TlOH(s)+2N2(g)+5H2O