Phosphoryl Chloride
Trending Questions
Q. Which of the following has pπ−dπ bonding?
- NO3-
- SO32-
- BO33-
- CO32-
Q. Which of the following d orbitals is not used in bonding to form H2SO4 ?
- dxy
- dyz
- dzx
- dz2
Q. Hybridisation involves the mixing of orbitals having comparable energies of same atom. Hybridised orbitals perform efficient overlapping than overlapping by pure s, p or d orbitals.
Consider the following compounds and select the incorrect statements among the following:
NH3, PH3, H2S, SO2, SO3, BF3, PCl3, IF7, P4, H2
Consider the following compounds and select the incorrect statements among the following:
NH3, PH3, H2S, SO2, SO3, BF3, PCl3, IF7, P4, H2
- Six molecules out of the following involves hybridisation
- Three molecules are hypervalent compounds
- Six molecules out of the above compounds are non-planar in structure
- Two molecules out of the given compounds involves (dπ−pπ) as well as also involves (pπ−pπ) bonding
Q. Which of the following is not formed on hydrolysis of PCl5?
- POCl3
- H3PO4
- HCl
- PCl3
Q. Which of the following statements is(are) correct regarding BF3:
- BF3 is covalent
- BF3 is a colourless gas
- The bond lengths in BF3 are significantly shorter than the sum of the covalent radii
- pz atomic orbital on B does not involve in hybridization
Q. Explain why (CH3)3C⊕ is more stable than CH3⊕CH2 and ⊕CH3 is less stable.
- Tautomerism
- Hyperconjugation
- Inductive effect
- Resonance
Q. In the presence of a small amount of water, PCl5 hydrolyses to form:
- PCl3
- H3PO3
- POCl3
- POCl
Q. The hybridisation of central atoms in N3−, NOCl and N2O respectively are:
- sp2, sp2, sp
- sp, sp2, sp
- sp, sp, sp3
- sp2, sp, sp
Q. Assertion :PCl4 exists but NCl5 does not exist. Reason: d− orbital in P−atom takes part in chemical bonding, this lacks in N− atom.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct
Q. In the presence of a small amount of water, PCl5 hydrolyses to form:
- PCl3
- H3PO3
- POCl3
- POCl
Q. In the compound of type POX3, P atom shows multiple bonding of the type:-
- pπ−dπ
- dπ−dπ
- pπ−pπ
- No multiple bonding
Q. Assertion :SF6 exists but SH6 does not. Reason: dπ−pπ bonding cannot take place in SH6
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct
Q. In monomeric BH3, let an axis definition place the molecule in the xz plane. Which atomic orbital on B is non-bonding?
- 2s
- 2px
- 2py
- 2pz
Q. If a molecule MX3 has zero dipole moment, the σ - bonding orbitals used by M (atomic number < 21) is:
- sp3 - hybridized
- pure p
- sp - hybridized
- sp2 - hybridized
Q. Hybridisation of iodine in IF7 molecule is:
- sp3
- sp3d
- sp3d2
- sp3d3
Q. The hybridisation of sulphur in SF4 is:
- sp2
- sp3d2
- sp3d
- sp3
Q. In the presence of a small amount of water, PCl5 hydrolyses to form:
- PCl3
- H3PO3
- POCl3
- POCl
Q. Increasing paramganetism of Ca, Al, O, N is Ca<Al<O<N.
if true enter 1, else enter 0.
if true enter 1, else enter 0.
- 1
Q. Among the following which one is a wrong statement?
- PH5 and BiCl5 do not exist
- pπ−dπ bonds are present in SO2
- SeF4 and CH4 have same shape
- I+3 has bent shape
Q. The pi acceptor ligand are those which possess vacant π-orbitals in addition to the lone pairs of e−, which of the following complex/ion has the highest M−C bond order?
- [V(CO)6]−
- Fe(CO)5
- Ni(CO)4
- [Mn(CO)6]+
Q. In the compound of type POX3, P atom shows multiple bonding of the type:-
- pπ−dπ
- dπ−dπ
- pπ−pπ
- No multiple bonding
Q. The HNH angle value is higher than HPH, HAsH and HSbH angles. Why?
Q. In the compound of type POX3, P atom shows multiple bonding of the type:-
- pπ−dπ
- dπ−dπ
- pπ−pπ
- No multiple bonding
Q. The hybridization of Xe and the number of lone pairs of electrons on it in XeF6 are:
- sp3d3, 1
- sp3d2, 2
- sp3d2, 1
- sp3d2, 0