Synthesis Using Azide & Gabriel Synthesis
Trending Questions
Why cannot aromatic primary amines be prepared by Gabriel phthalimide synthesis?
Which of the following amines cannot be prepared by Gabriel Synthesis?
Isopropyl amine
2-phenylethyl amine
Butyl amine
N -methyl benzyl amine.
The total number of monohalogenated organic products in the following (including stereoisomers) reaction is:
A (Simplest optically active alkene)
I. The major product will be ethyl nitrite in case of KNO2.
II. The major product will be nitroethane in case of KNO2.
III. The major product will be ethyl nitrite in case AgNO2.
IV. The major product will be nitroalkane in case AgNO2.
- I and II
- II and III
- I and IV
- III and IV
- ether, alkene, alcohol
- alcohol, ketone, ether
- alcohol, ketone, amine
- ether, amine, ketone
- Hoffmann Bromamide reaction
- Gabriel phthalimide synthesis
- Sandmeyer reaction
- Reaction with NH3
What volume of 1 M NaOH (in ml) will be required to react completely with 100g of oleum which is 109% labelled?
Which of the following method is used to prepare pure aliphatic primary amine
Gattermann - Koch reaction
GabrielPthalimide synthesis
Hoffmann degradation method
Carbylamine reaction
- C2H5Br and KCN
- C2H5Br and NH3
- C2H5Br and AgCN
- C2H5Br and HCN
Hydrolysis of XeF6
- CH3COCH2COOH
- CH3COOH
- CH2=CH−CH2−COOH
- CH3CH2COOH
(a) Gabriel phthalimide synthesis is not preferred for preparing aromatic primary amines.
(b) On reaction with benzene sulphonyl chloride, primary amine yields product soluble in alkali whereas secondary amine yields product insoluble in alkali.
- Primary Aromatic Amines
- Secondary Amines
- Primary Aliphatic Amines
- Tertiary Amines
Draw organic products formed in the following reaction.
- H3PO2
- CH3CH2OH
- H2O
- H3PO3
What are biodegradable polymers and non-biodegradable polymers? Write one example of each.
Explain cationic detergents.
both A and B in equal proportions- Only elimination occurs. Neither A nor B
- True
- False
The following dihaloalkanes gives an N-(haloalkyl)phthalimide on reaction with one equivalent of the potassium salt of phthalimide. Deduce the structure of the phthalimide derivative formed:
Both A and B in equal proportions
Neither A nor B are formed. An elimination product is formed rather.
- the crimping of wool
- the making of glue
- the dyeing industry
- fast-drying varnish
- Aniline
- Benzylamine
- Methyl amine
- Iso-butyl amine
The compound T is:
- glycine
- alanine
- valine
- serine
1. K2CO3 abstracts a proton to give a nucleophile
2. Phthalic acid reacts with ammonia to give phthalimide
3. Reaction of Nuleophile with 3-bromopropyne
4. Hydrolysis
- 2; 1; 3; 4
- 1; 3; 4; 2
- 1; 2; 3; 4
- 2; 1; 4; 3
- Aniline
- 4-bromoaniline
- o-toluidine
- Benzylamine
- N-methylethanamine