Angle between Two Vectors
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- √3+1√3
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- √3+1
Find the angle between two vectors a and b with magnitudes √3 and 2 respectively, having a.b=√6
The locus of a point that moves such that the difference of its distance from two fixed points is always a constant, is
a circle
a straight line
a hyperbola
an ellipse
→a and →c are unit vectors and |→b|=4. The angle between →a and →c is cos−1(14).
If →b−2→c=λ→a, then λ is
3 or −4
14 or 34
−3 or 4
−14 or 34
- π6
- π3
- 5π6
- 2π3
- π2
- π3
- sin−1√a2+b2+c2
- sin−1√p2+q2+r2
- π3
- π4
- π6
- none of these
Two vectors and each of magnitude are inclined to each other such that their resultant is to then the resultant of and is
2F
Column - I | Column - II |
(A) If →a=^j+√3^k, →b=−^j+√3 ^k and →c=2√3^k form a triangle, then internal angle of the triangle between →a and →b is | (p) π6 |
(B) If ∫ba(f(x)−3x)dx=a2−b2, then the value of f(π6) is | (q) 2π3 |
(C) The value of π2ln3∫5676sec(πx)dx is | (r) π3 |
(D) the maximum value of ∣∣∣Arg(11−z)∣∣∣|z|=1, z≠1 is given by | (s) π |
(t) π2 |
- A(r), B(p), C(s), D(t*)
- (−∞, −43)
- (−∞, 0)
- (−43, 0)
- (−43, ∞)
If the sum of two unit vectors is a unit vector, then the magnitude of the difference is
The vector in the direction of the vector ^i−2^j+2^k that has magnitude 9 is
(a) ^i−2^j+2^k
(b) ^i−2^j+2^k3
(c) 3(^i−2^j+2^k)
(d) 9(^i−2^j+2^k)
What is the value of ‘g’ when a body is thrown vertically upwards?
Does order matter for dot product?
If are three mutually perpendicular vectors equally inclined to at angle then find the value of .
Eliminate between () and ()
Choose the correct answer
If θ is the angle between two vectors a and b, then a.b≥0 only when
a) 0<θ<π2
b) 0≤θ<π2
c) 0<θ<π
d) 0≤θ≤π
- 315
- 256
- 84
- 336
- π6
- π4
- π3
- π2
- (1, 4)
- none of these
- (2, 4)
- [2, 4)
- π6
- π3
- 5π6
- 2π3
- →α
- →β
- →γ
- None of the above
then x lies in the interval:
- (12, 1)
- (0, 12)
- (1, 32)
- (12, 32)
- π6
- π4
- π3
- π2
- (114, 214, 314)
- (√14, √142, √143)
- (−1√14, −2√14, −314)
- (1√14, 2√14, 3√14)