Angle of Intersection of Two Circles
Trending Questions
Q. If the circle x2+y2+4x+22y+c=0 bisects the circumference of the circle x2+y2−2x+8y−d=0 (c, d>0), then the maximum possible value of cd is
- 125
- 425
- 625
- 25
Q. The common chord of the circles x2+y2−4x−4y=0 and 2x2+2y2=32 subtends at the origin an angle equal to
- π3
- π4
- π6
- π2
Q. The angle between the circles S1:x2+y2−4x+6y+11=0 and S2:x2+y2−2x+8y+13=0 is
- 60o
- 45o
- 30o
- 90o
Q. If the angle of intersection of the circles x2+y2+x+y=0 and x2+y2+x−y=0 is θ, then the equation of the line passing through (1, 2) and making an angle θ with the y-axis is
- x=1
- y=2
- x+y=3
- x−y=3
Q. If the angle of intersection of the circles x2+y2+x+y=0 and x2+y2+x−y=0 is θ, then the equation of the line passing through (1, 2) and making an angle θ with the y-axis is
- x=1
- y=2
- x+y=3
- x−y=3
Q. If the circle x2+y2+4x+22y+c=0 bisects the circumference of the circle x2+y2−2x+8y−d=0 (c, d>0), then the maximum possible value of cd is
- 25
- 125
- 425
- 625
Q. If the circle C1:x2+y2=16 intersects another circle C2 of radius 6 in such a manner that their common chord is of maximum length and has slope =12. Then the co-ordinates of the centre of the circle(s) C2 is/are
- (−2, −4)
- (2, 4)
- (−2, 4)
- (2, −4)
Q. The angle between the circles S1:x2+y2−4x+6y+11=0 and S2:x2+y2−2x+8y+13=0 is
- 90o
- 60o
- 45o
- 30o
Q. The equation of the straight line which passes through the point (2, −3) and makes an angle of π4 with the axis of x is
- x−y=5
- x−y=1
- x+y=5
- xy=1
Q. Number of real value of x satisfying the equation, arctan√x(x+1)+arcsin√x(x+1)+1=π2 is
- 1
- more than 2
- 2
- 0
Q.
If , then find the equation of the circle.
Q. If the angle of intersection of the circles x2+y2+x+y=0 and x2+y2+x−y=0 is θ, then equation of the line passing through (1, 2) and making an angle θ with the y − axis is
- x=1
- y=2
- x+y=3
- x−y=3
Q.
In in the given figure, △ABC is a right angle isosceles triangle with AB=BC=12 cm. An arc is drawn considering AR as the radius, if the area of region CPQ=BRQ, then the area of circle with radius AR is
(correct answer + 1, wrong answer - 0.25)
In in the given figure, △ABC is a right angle isosceles triangle with AB=BC=12 cm. An arc is drawn considering AR as the radius, if the area of region CPQ=BRQ, then the area of circle with radius AR is
(correct answer + 1, wrong answer - 0.25)
- 476 cm2
- 196π cm2
- 576 cm2
- 169π cm2
Q. Prove that the equation to a circle whose radius is a and which touches the axes of coordinates, which are inclined at an angle ω, is
x2+2xycosω+y2−2a(x+y)cotω2+a2cot2ω2=0.
x2+2xycosω+y2−2a(x+y)cotω2+a2cot2ω2=0.
Q.
In in the given figure, △ABC is a right angle isosceles triangle with AB=BC=12 cm. An arc is drawn considering AR as the radius, if the area of region CPQ=BRQ, then the area of circle with radius AR is
(correct answer + 1, wrong answer - 0.25)
In in the given figure, △ABC is a right angle isosceles triangle with AB=BC=12 cm. An arc is drawn considering AR as the radius, if the area of region CPQ=BRQ, then the area of circle with radius AR is
(correct answer + 1, wrong answer - 0.25)
- 476 cm2
- 196π cm2
- 169π cm2
- 576 cm2
Q.
The angle at which the circles (x−1)2+y2= 10 and x2+(y−2)2=5 intersect is
Q.
The angle at which the circles (x−1)2+y2= 10 and x2+(y−2)2=5 intersect is
π6
π4
π3
π2
Q. The mid point of chord 2x+y−5=0 of the parabola y2=4x is
- (1, 3)
- (2, 1)
- (3, −1)
- (52, 0)
Q. Find the equations of the lines for which cotθ=12, where θ is the angle of inclination of the line and y− intercept is −32
Q. If θ is the acute angle between the lines represented by equation ax2+2hxy+by2=0, then prove that tanθ=∣∣∣2√h2−aba+b∣∣∣, a+b≠0.