Auxiliary Circle of Hyperbola
Trending Questions
- x2+y2−24x−12=0
- x2+y2+24x−12=0
- x2+y2–12x+24=0
- x2+y2+12x+24=0
- radius of the auxiliary circle is √10
- conjugate axis of the hyperbola is 2√22
- the directrix of the hyperbola corresponding to the focus (5, 6) is 2x+2y=11
- the point of contact of the tangent with the hyperbola is (23, 9)
- (x+1)2+(y+5)2=25
- x2+y2=25
- x2+y2=16
- (x+1)2+(y+5)2=16
For all four circles and , the following four equations are given:
Circle
Circle
Circle
Circle
If the centre of circle is joined with the centre of the circle , further centre of circle is joined with the centre of the circle , centre of circle is joined with the centre of circle and lastly, the centre of circle is joined with the centre of circle , then these lines form the sides of :
Rectangle
Square
Parallelogram
Rhombus
- x2+y2=100
- x2+y2=28
- x2+y2=64
- x2+y2=36
The radius of the circle is
- y2−x2=18
- x2−y2=5
- y2−x2=5
- x2−y2=18
- x2−y2=16
- x2−y2=32
- x2−y2=8
- x2−y2=64
The distance between the foci =16 and eccentricity =√2
How many asymptotes does a hyperbola have?
- (x+1)2+(y+5)2=25
- x2+y2=25
- x2+y2=16
- (x+1)2+(y+5)2=16
- √a2−b22
- √a2+b22
- √a2−b2
- 12√a2−b2
A standard hyperbola is given as below. Which among the points given would lie on the auxiliary circle of the hyperbola?
A
B
O
- 320
- 540
- 1340
- 340
What is the equation of the auxiliary circle of a hyperbola
x216−y29=1
x2+y2=9
x2+y2=16
x2+y2=25
x2+y2=1
- 6π(2+√3)2
- π6(2+√3)2
- π3(2+√3)2
- 3π2+√3)2
A standard hyperbola is given as below. Which among the points given would lie on the auxiliary circle of the hyperbola?
A
B
O
S1
- x2+y2=100
- x2+y2=28
- x2+y2=64
- x2+y2=36
If a circle cuts a rectangular hyperbola xy=c2 in A, B, C, D and the parameters of these four points be t1, t2, t3 and t4 respectively. Then if the eccentricity of a conic is equal to t1.t2.t3.t4, the conic can't be
- Circle
- Parabola
- Ellipse
- Hyperbola
A standard hyperbola x2a2−y2b2=1 is drawn along with its auxiliary circle. A point P (a secθ, btanθ) is taken. A perpendicular is dropped from P to the x axis which meets at the axis at R. A tangent is drawn from R to auxiliary circle. Which angle is equal to θ
- r2+r[4cos(θ−π6)+3cos(θ−π3)]+6√3=0
- r2−r[4cos(θ−π6)+3cos(θ−π3)]+6√3=0
- r2+r[4cos(θ−π6)−3cos(θ−π3)]+6√3=0
- r2−r[4cos(θ−π6)+3cos(θ−π3)]−6√3=0
- False
- True