Composition of Trigonometric Functions and Inverse Trigonometric Functions
Trending Questions
If cos(a+b)=4/5, sin(a-b)=5/13 and 0<a, b<pi/4, then tan2a=?
If then
Sin A Sin(A+2B) - Sin B Sin(B+2A) = Sin(A-B)Sin (A+B)
Value of sin[1/4arc sin((√63)/8)
- 12
- 1
- 2
- 23
If sinA+sinB=a and cosA+ cosB= b then the value of cos(A+B) is
Sin 10° + Sin 20° + Sin 40°+ Sin 50° = Sin 70°+ Sin 80°
sin10sin30sin50sin70 = 1/16
If cos a + cos b + cos c = 0 = sin a + sin b + sin c
cos2a + cos2b + cos2c = ?
- 865
- 2465
- 1665
- 5665
Prove that
[1/(sec²x-cos²x) + 1/(cosec²x-sin²x)] sin²x cos²x =
(1-sin²x cos²x)/(2+sin²x cos²x)
- −3132
- 34
- −√74
- −37
If then
None of these
Integrate dx/sinx+√3cosx
cos6 π/16 + cos6 3π/16 + cos6 5π/16 + cos6 7π/16 = ?
if a = cos 2B + cos 2A. , b= cos 2B - cos 2 A
c= sin 2A+ sin 2B, d= sin = sin2A-sin2B
Then which of the first is true.
(A) a/b= cot(A+B) cot(A-B)
(B) c/d= tan(A+B)/ tan(A-B)
(C ) b/ c= tan(A-B)
(D) none of these
If in , then
is
is
cannot be evaluated.
is
tan[sec−1√1+x2]=
1x
x
- 1√1+x2
x√1+x2
- 3π4
- π4
- π3
- π6
Evaluate sin(π\n)+sin(3π\n)+sin(5π\n)+...to n terms
- y=tan(cos−1x);y=√1−x2x
- y=tan(cot−1x);y=1x
- y=sin(tan−1x);y=x√1+x2
- y=cos(tan−1x);y=sin(cot−1x)
- 0
- 4
- 2
- 5
How is sinA+sinB+sinC=4 cosA/2 cosB/2 cosC/2