Condition for Monotonically Decreasing Function
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- If f(x) is increasing on [a, b], then f(x)≥0 on (a, b)
- If f(x) attains a minimum at x=c where a<c<b, then f′(c)=0
If f(x) , g(x) and h(x) are three differentiable functions throughout their domains and given that their first derivatives are -
f′(x)<0
g′(x)=0
h′(x)≤0
throughout their domains. Then choose the correct option of monotonically decreasing functions -
f(x) & h(x)
g(x) & h(x)
f(x), g(x) & h(x)
Only h(x)
- g is increasing on J
- g is decreasing on J
- g is concave up on J
- g is concave down on J
Which of the following is a monotonically decreasing function?
f(x) = ln (x)
f(x) = 3 - x3
f(x) = ex
f(x) = 1/ x2
- is always non-positive
- is always non-negative
- can take positive or negative values
- can't be determined
- n+1∫0f(x)dx−n∫0f(x)dx=n−1lnn
- n+1∫0g(x)dx−n∫0g(x)dx=1n+1
- t∫0f(x)dx=t∫0g(x)dx has at least one solution in t∈(0, π2)
- e<limn→∞n∫0g(x)dx<e2
- f(x)=ex+2ex
- f(x)=ex−2e2x
- c=−11+2e
- c=13−2e
Which of the following is a monotonically decreasing function?
f(x) = ln (x)
f(x)=3−x3
f(x)=ex
f(x)=1x2
- dependent on λ
- a non zero constant
- zero
- λ2
- None of these
- (0, e)
- (1, e)
- (e, ∞)
- f′(x)<f(x), 0<x<14
- f′(x)<f(x), 14<x<34
- f′(x)<f(x), 34<x<1
- f′(x)>f(x), 0<x<14
- None of these
- (1, e)
- (e, ∞)
- (0, e)
- f(0)<0
- f(x) is a decreasing function ∀ x∈R
- f(x) is a increasing function ∀ x∈R
- 1∫0f(x) dx>0
- 2.5<p<3
- p>3
- 1.5<p<2
- 2<p<2.5
- −1<x<3
- 1<x<3
- −3<x<1
- None of these
- 9
- 5
- 4
- 20
If f(x) , g(x) and h(x) are three differentiable functions throughout their domains and given that their first derivatives are -
f′(x)<0
g′(x)=0
h′(x)≤0
throughout their domains. Then choose the correct option of monotonically decreasing functions -
Only h(x)
f(x) & h(x)
g(x) & h(x)
f(x), g(x) & h(x)
- g is increasing on J
- g is decreasing on J
- g is concave up on J
- g is concave down on J
- Domain=R−{−4}, Range ={−1, 1}
- Domain =R−{1}, Range R
- Domain =R, Range ={–1, 1}
- Domain=R−{4}, Range ={−1}
- (0, e)
- (1, e)
- (e, ∞)
- R
1) f(x)=x1/3 at x=0
Which of the following is a monotonically decreasing function?
f(x) = ln (x)
f(x)=1x2
f(x)=3−x3
f(x)=ex
- (−1, 12]
- (−∞, ∞)−{−1, 1}
- (−∞, −1)∪([12, ∞)−{1})
- (−∞, 12]−{−1}
- f(0)<0
- f(x) is a decreasing function ∀ x∈R
- f(x) is a increasing function ∀ x∈R
- 1∫0f(x) dx>0
S2: If f(x) is decreasing function with downward concavity, then concavity of f−1(x) is upwards.
- S1 and S2 both are true
- S1 is true and S2 is false
- S1 is false and S2 is true
- S1 and S2 both are false
- (0, e−12)
- (e−12, e−1)
- (e−1, 2e−1)
- (2e−1, 2e)
- x<−3
- |x|>3
- |x|<3
- x>3
- (−∞, 12]−{−1}
- (−1, 12]
- (−∞, ∞)−{−1, 1}
- (−∞, −1)∪([12, ∞)−{1})