Condition for Monotonically Increasing Function
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Let be all non-zero and satisfy . If the matrix , satisfies , then value of can be:
If
(S1) There exists x1, x2∈(2, 4), x1<x2, such that f′(x1)=−1 and f′(x2)=0
(S2) There exists x3, x4∈(2, 4), x1<x4, such that f is decreasing in (2, x4), increasing in (x4, 4) and 2f′(x3)=√3f(x4)
- Both (S1) and (S2) are true
- Both (S1) and (S2) are false
- (S1) is true and (S2) is false
- (S1) is false and (S2) is true
where a, b and d are non-zero real constants, Then :
- f is an increasing function of x
- f is a decreasing function of x
- f is neither increasing nor decreasing function of x
- f′ is not a continuous function of x
- f(x)=g(x) has exactly one solution.
- f(x)=g(x) has exactly two solutions.
- f(x)−g(x)→∞ as x→−∞
- The minimum value of f(g(x)) is −1.
- π8
- 3π4
- π3
- 2π3
If the , and terms of a GP are and respectively. Prove that
In the interval the function is:
Increasing
Decreasing
Neither increasing nor decreasing
None of the above
On the interval the function is
Strictly decreasing
Strictly increasing
Decreasing in (2, 3) only
Neither increasing nor decreasing
If and are differentiable functions such that and , then find the numbers indicated in problem .
0<x<2π. Then
- b
- c
- a
- d
- True
- False
- 0 (zero)
- −1
- 1
- i
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct
- None of these
- a=1, b=1/√2+π/6
- a=1/√2, b=1/√2
- a=1, b=√3/2−π/6
- a=√3/2, b=√3/2+π/6
Which of the following function is a monotonically increasing function?
f(x)=x3+2x
f(x)=x3+2x
f(x)=x2+2x
f(x)=cosx
Which of the following condition is true for a monotonically increasing function f(x), which is differentiable in its domain?
f’(x) > 0
f’(x) ≥ 0
f’(x) < 0
f’(x) ≤ 0
where a, b and d are non-zero real constants, then :
- f is an increasing function of x
- f is neither increasing nor decreasing function of x
- f is a decreasing function of x
- f′ is not a continuous function of x
Which of the following condition is true for a monotonically increasing function f(x), which is differentiable in its domain?
f′(x)>0
f′(x)≥0
f′(x)<0
f′(x)≤0
- None of these
- −(n2−a2)y2
- (n2+a2)yn
- (n2−a2)yn
- −(n2+a2)yn
Which of the following function is a monotonically increasing function?
f(x) = x2 +2x
f(x) = x3 + 2x
f(x) = x3 + 2x
f(x) = cos x
Reason (R): f(x) is neither increasing nor decreasing function.
- Both (A) and (R) are true and (R) is the correct explanation of (A).
- (A) is true but (R) is false.
- (A) is false but (R) is true.
- Both (A) and (R) are true and (R) is not the correct explanation of (A).
- is equal to 1
- is not defined
- lies in (1, 2)
- is more than 2
- ddx(g(3n−2)(x))=1 (whenever exists) for n∈N
- ddx(g(3n)(x))=1 (whenever exists) for n∈N
- limx→1100∑r=1(g3r(x))r+x−101x−1=5050
- Equation of the tangent to the curve y=g80(x) when x=2 is x−y−3=0