Condition for Three Vectors to Form a Triangle
Trending Questions
Q. Let △xyz be a triangle and →a=−−→YZ, →b=−−→ZX, →c=−−→XY. If |→a|=6, |→c|=14, →a⋅→b=30, then the values of |→a×→b+→b×→c|2100 is
Q. In a triangle ABC, if 2−−→AC=3−−→CB and 2−−→OA+3−−→OB=λ⋅−−→OC, then λ is
Q. If →x and →y are two non-collinear vectors and ABC is a triangle whose side length satisfying (5a−12b)→x+(26b−10c)→y+(12c−13a)(→x×→y)=→0, then which of the following is/are correct ?
- △ABC is an acute angle triangle
- △ABC is right angle triangle
- △ABC is an obtuse angle triangle
- ∠B=90∘
Q. Let △xyz be a triangle and →a=−−→YZ, →b=−−→ZX, →c=−−→XY. If |→a|=6, |→c|=14, →a⋅→b=30, then the values of |→a×→b+→b×→c|2100 is
Q. If , then is it true that ? Justify your answer.
Q. In triangle ABC which of the following is not true: A. B. C. D.
Q.
3 vectors ¯a, ¯b, ¯c can always form the sides of a triangle if ¯a+¯b+¯c=0
True
False
Q.
The given vectors can form sides of a triangle ^i−^j−^k, −2^i+3^j−^k, ^i−2^j+2^k
True
False
Q. If →x and →y are two non-parallel vectors and ABC is a triangle with side lengths a, b and c satisfying (20a−15b)→x+(15b−12c)→y+(12c−20a)(→x×→y)=→0, then triangle ABC is
- an acute-angled triangle
- an obtuse-angled triangle
- a right-angled triangle
- an isosceles triangle
Q. If →x and →y are two non-parallel vectors and ABC is a triangle with side lengths a, b and c satisfying (20a−15b)→x+(15b−12c)→y+(12c−20a)(→x×→y)=→0, then triangle ABC is
- an acute-angled triangle
- an obtuse-angled triangle
- a right-angled triangle
- an isosceles triangle
Q. Let →a be a unit vector and →b be a non-zero vector not parallel to →a. If two sides of a triangle are represented by the vectors √3(→a×→b) and →b−(→a.→b)→a, then the angles of the triangle are
- 300, 900, 600
- 450, 450, 900
- 600, 600, 600
- none of these
Q. Determine the missing parts of triangle ABC from the given information.
a=7, b=24, c=26
a=7, b=24, c=26
Q. The value of ∫a1[x]f′(x)dx, a>1, where [x] denotes the greatest integer less than or equal to x, is
- af([a])−(f(1)+f(2)+……+f(a))
- [a]f([a])−(f(1)+f(2)+……+f(a))
- af(a)−(f(1)+f(2)+……+f(a))
- [a]f(a)−(f(1)+f(2)+……+f(a))
Q.
Fill in the given blank.
We ________ construct when and
Q. Assertion :If [x] stands for greatest integer function, then the value of ∫153[x2]dx[x2−36x+324]+[x2] is 6 Reason: ∫baf(x)f(x)+f(a+b−x)dx=b−a2
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Both Assertion and Reason are incorrect
Q. (−3x2+5x−2)−2(x2−2x−1)
If the expression above is rewritten in the form ax2+bx+c, where a, b and c are constants, what is the value of b?
If the expression above is rewritten in the form ax2+bx+c, where a, b and c are constants, what is the value of b?
- 9
- 1
- 3
- 8
Q.
Integrate:
∫(x2+4x+3)dxQ. The value of ∫20[x+[x+[x]]]dx, (where [.] denotes the greatest integer function), is equal to
- 3
- 2
- none of these
- −3
Q.
The given vectors can form sides of a triangle ^i−^j−^k, −2^i+3^j−^k, ^i−2^j+2^k
True
False
Q. If ABCDEF is a regular hexagon and −−→AB+−−→AC+−−→AD+−−→AE+−−→AF=λ −−→AD, then λ =
- 2
- 3
- 4
- 6
Q. If ABCDEF is a regular hexagon and −−→AB+−−→AC+−−→AD+−−→AE+−−→AF=λ −−→AD, then λ =
- 2
- 6
- 3
- 4
Q. Evaluate (using formulae) 0.3×0.3×0.3+0.1×0.1×0.10.3×0.3−0.3×0.1+0.1×0.1
- 0.5
- 0.4
- 0.3
- 0.2
Q. If →x and →y are two non-parallel vectors and ABC is a triangle with side lengths a, b and c satisfying (20a−15b)→x+(15b−12c)→y+(12c−20a)(→x×→y)=→0, then triangle ABC is
- an acute-angled triangle
- an obtuse-angled triangle
- a right-angled triangle
- an isosceles triangle
Q. △ABC with vertices A (-2, 0), B (2, 0) and C (0, 2) is similar to △DEF with vertices D (-4, 0) E (4, 0) and F (0, 4).
State whether the following statement is true or false.
Enter 1 for true and 0 for false
Q.
3 vectors ¯a, ¯b, ¯c can always form the sides of a triangle if ¯a+¯b+¯c=0
True
False