Corresponding Points : Hyperbola

Q. The equation of the reflection of the hyperbola $\frac{(x-4{)}^2}{16}-\frac{(y-3{)}^2}{9}=1$ about the line $x+y-2=0$ is

1. $\frac{(x+3{)}^2}{16}-\frac{(y+4{)}^2}{16}=1$
2. $\frac{(x+2{)}^2}{16}-\frac{(y+1{)}^2}{9}=-1$
3. $\frac{(x+1{)}^2}{9}-\frac{(y+2{)}^2}{16}=-1$
4. $\frac{(x+1{)}^2}{16}-\frac{(y+2{)}^2}{9}=-1$

Q. $\frac{xdx-ydy}{xdy-ydx}=\sqrt{\frac{1+x^2-y^2}{x^2-y^2}}$

1. $\sqrt{x^2-y^2}+\sqrt{1+x^2-y^2}=c\left(\frac{x-y}{\sqrt{x^2-y^2}}\right)$
2. $\sqrt{x^2-y^2}+\sqrt{1+x^2+y^2}=c\left(\frac{x-y}{\sqrt{x^2+y^2}}\right)$
3. $\sqrt{x^2-y^2}+\sqrt{1+x^2-y^2}=c\left(\frac{x+y}{\sqrt{x^2-y^2}}\right)$
4. $\sqrt{x^2+y^2}+\sqrt{1+x^2-y^2}=c\left(\frac{x+y}{\sqrt{x^2+y^2}}\right)$

Q. The equation of the reflection of the hyperbola $\frac{(x-4{)}^2}{16}-\frac{(y-3{)}^2}{9}=1$ about the line $x+y-2=0$ is

1. $\frac{(x+3{)}^2}{16}-\frac{(y+4{)}^2}{16}=1$
2. $\frac{(x+2{)}^2}{16}-\frac{(y+1{)}^2}{9}=-1$
3. $\frac{(x+1{)}^2}{9}-\frac{(y+2{)}^2}{16}=-1$
4. $\frac{(x+1{)}^2}{16}-\frac{(y+2{)}^2}{9}=-1$

Q. The equation of the reflection of the hyperbola $\frac{(x-4{)}^2}{16}-\frac{(y-3{)}^2}{9}=1$ about the line $x+y-2=0$ is

1. $\frac{(x+3{)}^2}{16}-\frac{(y+4{)}^2}{16}=1$
2. $\frac{(x+2{)}^2}{16}-\frac{(y+1{)}^2}{9}=-1$
3. $\frac{(x+1{)}^2}{9}-\frac{(y+2{)}^2}{16}=-1$
4. $\frac{(x+1{)}^2}{16}-\frac{(y+2{)}^2}{9}=-1$