Diameter : Hyperbola
Trending Questions
Q. The locus of the centroid of the triangle formed by any point P on the hyperbola 16x2−9y2+32x+36y−164=0, and its foci is
- 16x2−9y2+32x+36y−36=0
- 9x2−16y2+36x+32y−144=0
- 9x2−16y2+36x+32y−36=0
- 16x2−9y2+32x+36y−144=0
Q. If two distinct tangents can be drawn from the point (α, 2) on different branches of the hyperbola
x29−y216=1, then
x29−y216=1, then
- |α|<32
- |α|>23
- |α|>3
- α=1
Q. The diameter of \(16x^2- 9 y^2 = 144\) which is conjugate to x = 2y, is
Q.
The radius of the circle with the polar equation is
Q. If θ is the acute angle between the tangents drawn from (1, 4) to the parabola y2=12x, then the value of sinθ+2cosθ is equal to
- √5
- √3
- 2
- 1
Q. The circle x2+y2−8x=0 and hyperbola x29−y24=1 intersect at point A and B. The equation of circle with AB as diameter is:
- x2+y2−12x+24=0
- x2+y2+12x+24=0
- x2+y2+29x−12=0
- x2+y2−24x−12=0
Q. If the tangent to the curve y=ex at a point (c, ec) and the normal to the parabola y2=4x at the point (1, 2) intersect at the same point on the x-axis, then the value of c is
Q. The circle x2+y2−8x=0 and hyperbola x29−y24=1 intersect at point A and B. The equation of circle with AB as diameter is:
- x2+y2+12x+24=0
- x2+y2−12x+24=0
- x2+y2+29x−12=0
- x2+y2−24x−12=0
Q. L:x2+2gxy+y2=0 represents the equation of pair of straight lines passing through the origin. If L makes an acute angle of θ with the straight line y=x, then
- sec2θ=−g
- cosθ=√g−12g
- tanθ=√g+1g−1
- cotθ=√g+1g−1
Q. Evaluate:
(0.43)3+(1.47)3+(1.1)3−3×0.43×1.47×1.1(0.43)2+(1.47)2+(1.1)2−0.43×1.43−0.43×1.1−1.47×1.1
(0.43)3+(1.47)3+(1.1)3−3×0.43×1.47×1.1(0.43)2+(1.47)2+(1.1)2−0.43×1.43−0.43×1.1−1.47×1.1
- 1.90
- 2.87
- 3
- 3.47
Q. The diameter of \(16x^2- 9 y^2 = 144\) which is conjugate to x = 2y, is
- y=16x9
- y=32x9
- x=16y9
- x−32y9
Q. If two distinct tangents can be drawn from the point (α, 2) on different branches of the hyperbola
x29−y216=1, then
x29−y216=1, then
- |α|<32
- |α|>23
- |α|>3
- α=1