Double Ordinate of Ellipse
Trending Questions
Q. If a tangent to the ellipse x2+4y2=4 meets the tangents at the extremities of its major axis at B and C, then the circle with BC as diameter passes through the point
- (−1, 1)
- (√3, 0)
- (1, 1)
- (√2, 0)
Q. The area of the region bounded by y−x=2 and x2=y is equal to
- 23
- 43
- 163
- 92
Q. The area bounded by the curve y=x3, x-axis and two ordinates x=1 to x=2 equal to
- 152sq.unit.
- 154sq.unit.
- 172sq.unit.
- 174sq.unit.
Q.
Let be a given ellipse, length of whose latus rectum is . If its eccentricity is the maximum value of the function, , then is equal to:
Q.
What are the three dimensions?
Q.
The parametric representation of a point on the ellipse whose foci are and and eccentricity is
None of the above
Q. The area included by the curve y=lnx, x−axis and the two ordinates at x=1e and x=e is
- 2−2e
- 1−1e
- 2e
- 1e
Q.
For the ellipse , the eccentricity is equal to
Q. If the point P on the curve, 4x2+5y2=20 is farthest from the point Q(0, −4), then PQ2 is equal to:
- 48
- 29
- 21
- 36
Q. If the double ordinate of the ellipse x236+y216=1 passes through the (5, 2), then the equation of double ordinate is
- y=2
- x=5
- x=6
- y=4
Q.
What is the eccentricity of an ellipse?
Q. Eccentricity of ellipse x2a2+1+y2a2+2=1is1√3 then length of Latus rectum is
- 2√3
- 4√3
- 2√3
- √32
Q. The equation of the latus rectum of the ellipse 9x2+4y2−18x−8y−23=0 are
- y=±√5
- y=−√5
- y=1±√5
- y=−1±√5
Q. If the latus rectum of an ellipse x2tan2φ+y2sec2φ= 1 is 1/2, then φ is
- π/6
- π/2
- π/3
- 5 π/12
Q. If (1+i1−i)3−(1−i1+i)3=x+iy, find(x, y).
Q. The equation of the latusrecta of the ellipse 9x2+42−18x−8y−23=0 are
- x=1±√5
- y=±√5
- x=±√5
- y=1±√5
Q.
If the latus-rectum of an ellipse is one half of its minor axis, then its eccentricity is
- 12
- √34
- √32
- 1√2
Q. Find the eccentricity, foci and the length of the latus-rectum of the ellipse x2+4y2+8y−2x+1=0.
Q. If the eccentricity of an ellipse is 58 and the distance between its foci is 10, then find the latus rectum of the ellipse.
Q. If the normal at the end of latus rectum of the ellipse x2a2+y2b2=1 passes through (0, −b), then e4+e2 (where E is eccentricity) equals
- square of the eccentricity is equal to the ratio of the minor and major axes
- ratio of the minor and major axes is √5+12
- eccentricity of the ellipse is √√5−12
- none of these
Q. Find the value of a for which the ellipse x2y2+y2b2=1, (a>b), if the extremities of the latus rectum of the ellipse having positive ordinates lie on the parabola x2=−2(y−2).
Q. If the length of the latusrectum of the ellipse x2tan2α+y2sec2α=1 is 12, then α =
- none
Q. If the latus rectum of an ellipse is equal to half of minor axis, find its eccentricity.
Q. AB is a diameter of x2+9y2=25. The eccentric angle of A is π6. Then the eccentric angle of B is
- 5π6
- −5π6
- π3
- −2π3
Q. Locus of the point which divided the double ordinates of the ellipse x2a2+y2b2=1 in the ratio 1:2 internally is
- x2a2+9y2b2=1
- x2a2+9y2b2=19
- 9x2a2+9y2b2=1
- 9x2a2+9y2b2=19
Q. Statement-1 : Eccentricity of ellipse whose length of latus rectum is same as distance between is 2sin18o
Statement-2 : For x2a2+y2b2=1, eccentricity e=√1−b2a2
Statement-2 : For x2a2+y2b2=1, eccentricity e=√1−b2a2
- STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is correct explanation for STATEMENT-1
- STATEMENT-1 is true, STATEMENT-2 is true and STATEMENT-2 is not correct explanation for STATEMENT-1
- STATEMENT-1 is true, STATEMENT-2 is false
- STATEMENT-1 is false, STATEMENT-2 is true
- Both STATEMENTS are false
Q. The eccentricity of an ellipse is √32 its length of latus reetum is
- 12 (length of major axis)
- 14 (length of major axis)
- 23 (length of major axis)
- 13 (length of major axis)
Q. If the eccentricity of an ellipse is 58 and the distance between its foci is 10, then find latus rectum of the ellipse.
Q. The length of latus rectum of the ellipse 4x2+9y2=36 is
- 43
- 83
- 6
- 12
Q. Find the eccentricity of that ellipse, whose latus rectum is half of the minor axis.