Equality of 2 Complex Numbers
Trending Questions
2z−n2z+n=2i–1 for some natural number n. Then
- n=20 and Re(z)=10
- n=20 and Re(z)=−10
- n=40 and Re(z)=10
- n=40 and Re(z)=−10
- 48 sq. units
- 32 sq. units
- 40 sq. units
- 80 sq. units
If z is a complex number, then z.¯z = 0 if and only if
z=0
Re(z)=0
Im(z)=0
None of these
If , then prove that .
For every real number c≥0, find all the complex number z which satisfy the equation
|z|2 - 2iz + 2c(1 + i) = 0
c + i( -1 Where 0
c + i( -1) Where 0 - 1
c + i( -2) Where c > -1
c + i( -2) Where 0
- four real and distinct roots
- three real and distinct roots
- two real and distinct roots
- only one real root
The imaginary part of is
If and then at is equal to
- Modulus of (z5−iz) is √2
- Modulus of (z4−iz) is 1
- Principal argument of (z5−iz) is π4
- Principal argument is (z5−iz) is π2
The sum of distinct values of λ for which the systems of equations
(λ−1)x+(3λ+1)y+2λz=0
(λ−1)x+(4λ−2)y+(λ+3)z=0
2x+(3λ+1)y+3(λ−1)z=0
has non-zero solutions, is
- 4 sq. units
- 8 sq. units
- 2 sq. units
- 1 sq. unit
(where C is constant of integration)
- ln∣∣1+√2+x2∣∣+C
- −ln∣∣1+√2−x2∣∣+C
- −xln∣∣1−√2−x2∣∣+C
- xln∣∣1−√2+x2∣∣+C
- x=511, y=711
- x=513, y=713
- x=511, y=713
- x=513, y=1413
- one
- infinitely many
- two
- four
- 1
- −2
- 0
- 2
If α, β be the roots of x2+px+q=0 and α+h, β+h are the roots of x2+rx+s=0 , then
- z=−3+2i
- z=3+2i
- z=−3−2i
- z=3−2i
If point lies on the straight line and the point lies on the straight line , then the equation of the line PQ is
- a>c and b>d
- a>c and b=d=0
- a+c>b+d
- a=c=0 and b>d
Find the real values of x and y, if
(i) (x+i y)(2−3i)=4+i(ii) (3x−2i y)(2+i)2=10(1+i)(iii) (1+i)x−2i3+i+(2−3i)y+i3−i=i(iv) (1+i)(x+i y)=2−5i
- 1
- 2
- 4
- 5
- a=710, b=−135
- a=710, b=−115
- a=711, b=−1310
- a=711, b=−135
If x<0 is a real number, then arg(x)=
- −π4
- π4
- 3π4
- 3π4
Column 1Column 2a. The set of points z satisfying |z−i|z||=|z+i|z|| p. an ellipse with eccentricity 45 is contained in or equal to b. The set of points z satisfying |z+4|+|z−4|=10 q. the set of points z satisfying is contained in or equal to Img z=0 c. If |w|=2, then the set of points z=w−1w r. the set of points z satisfying is contained in or equal to |Img z|≤10 d. If |w|=1, then the set of points z=w+1w s. the set of points z satisfying is contained in or equal to |Re z|<2 t. the set of points z satisfying |z|≤3
- a−q, r; b−p; c−p, s, t; d−q, r, t
- a−p, q, r; b−p; c−s, t; d−q, r, t
- a−q, r; b−p, t; c−p, t; d−q, r
- a−p, r; b−p, q; c−s, t; d−p, r
- 4(x2−y2)
- 4(x2+y2)
- 2(x2−y2)
- 2(x2+y2)