Equation of Circle with Origin as Center
Trending Questions
- The maximum area of △AOB is 4 sq. units
- The maximum area of △AOB is 8 sq. units
- When the area of △AOB is maximum, then slope of line AB is −12√2
- When the area of △AOB is maximum, then slope of line AB is −18√2
The equation of a circle which cuts the three circles
x2 + y2 − 3x − 6y + 14 = 0,
x2 + y2 − x − 4y + 8 = 0
x2 + y2 + 2x − 6y + 9 = 0
orthogonally is –––––––––––––––
x2 + y2 - 2x - 4y + 1 = 0
x2 + y2 + 2x + 4y + 1 = 0
x2 + y2 - 2x + 4y + 1 = 0
x2 + y2 - 2x - 4y - 1 = 0
If one of the diameters of the circle is a chord of another circle ‘’ whose center is at , then its radius is
- 13
- 12
- 14
- 16
Find the equation of director circle of the circle whose diameters are 2x - 3y + 12 = 0 and x + 4y - 5 = 0 and area is 154 square units.
The equation of the circle passing through the origin which cuts off intercept of length 6 and 8 from the axes is
x2+y2−12x−16y=0
x2+y2+12x+16y=0
x2+y2+6x+8y=0
x2+y2−6x−8y=0
- x2+y2−ax−by=0
- x2−y2−ax−by=0
- x2+y2+ax−by=0
- x2+y2+ax+by=0
- 6x−y=0
- 3x+2y=0
- x+3y=0
- 3x−y=0
- −52
- −32
- 52
- 32
The area in the first quadrant between and is
- x2+y2=9
- x2+y2=16
- x2+y2=25
- x2+y2+6x+8y+25=0
Find the equation of the circle which passes through the origin and cuts off chords of lengths 4 and 6 on the positive side of the x-axis and y-axis respectively.
- 8
- 8√5
- 4√5
- 12
- X2−Y2=c2
- X2−Y2=2c2
- X2+Y2=c2
- X2+Y2=2c2
- 75∘
- 45∘
- 37.5∘
- 90∘
- x2+y2+ax−by=0
- x2+y2−ax−by=0
- x2−y2−ax−by=0
- x2+y2+ax+by=0
- a straight line of slope 12
- a circle with centre (0, 0)
- a straight line passing through (0, 0)
- a circle with radius 1√2 units
- An ellipse
- A circle
- A parabola
- A hyperbola
- 12, 12
- 12, −√2
- 32, 12
- 12, 32
- (4√3−π)
- (√3−π)
- (163π)
- (8π3+8√3)
- A2a
- Aa
- 2Aa
- 4Aa
- A hyperbola
- A rectangular hyperbola
- An ellipse
- None of these
- a parabola
- a circle
- an ellipse
- a pair of straight lines
- (4−π)3/2
- 43(4−π)3/2
- 83(4−π)3/2
- 83(4−π)