Equation of Family of Circles Passing through Point of Intersection of Two Circles
Trending Questions
Q. The equation of the circle passing through the point (–2, 4) and through the points of intersection of the circle x2+y2−2x−6y+6=0 and the line 3x + 2y - 5 = 0, is
- x2+y2−3x−4y=0
- x2+y2+4x−2y−4=0
- x2+y2+2x−4y−4=0
- x2+y2−4x−2y−4=0
Q.
The equation of the circle passing through and the points of intersection of and is
None of these
Q. The equation of the circle passing through (1, 1) and the points of intersection of x2+y2+13x−3y=0 and 2x2+2y2+4x−7y−25=0 is
- x2+y2+15x−13y−25=0
- 2x2+2y2+25x−13y−30=0
- 4x2+4y2+30x−13y−25=0
- 4x2+4y2+25x−13y−30=0
Q. If one end of the diameter of the circle x2+y2−8x−4y+c=0 is (−3, 2) then other co-ordinate is
- (6, 2)
- (5, 3)
- (1, −8)
- (11, 2)
Q. The equation of the image of the circle x2+y2+16x−24y+183=0 along the line mirror 4x+7y+13=0 is:
- x2+y2+32x−4y+235=0
- x2+y2+32x+4y−235=0
- x2+y2+32x−4y−235=0
- x2+y2+32x+4y+235=0
Q.
Find the equation of family of circles through the intersection of x2 + y2 − 6x + 2y + 4 = 0 and x2 + y2 + 2x − 4y − 6 = 0 whose center lies on y = x.