Equation of Parabola When Its Axis Is Parallel to X or Y Axis
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In what ratio the line divides the line joining the points and
The straight line divides the line segment joining the points and in the ratio
externally
internally
internally
externally
If the line passes through the point which divides the segment joining the points and in the ratio , then is equal to
- both the tangents will always be perpendicular to each other
- extremities of the focal chord and intersection point of the tangents will lie on the circles discribed on the focal chord as diameter
- both the tangents need not be perpendicular to each other
- tangents will intersect each other at directrix
Find the length of the line segment joining the vertex of the parabola y2=4ax and a point on the parabola where the line-segment makes an angle θ to the x-axis.
- x(t3+t1)(t21t23+1)=2yt1t3(t1t3+1)
- x(t3−t1)(t21t23+1)=2yt1t3(t1t3+1)
- x(t3−t1)(t21t23+1)+2yt1t3(t1t3+1)=0
- x(t3+t1)(t21t23−1)+2yt1t3(t1t3+1)=0
- 13
- 23
- 43
- 53
- λ2=8
- λ3=6
- λ3=8
- λ2=6
- 16y=29
- 16x=19
- 16x=13
- 16y=35
The point which divides the line segment joining the points and in the ratio internally lies in the
I quadrant
II quadrant
III quadrant
IV quadrant
- (0, 2]
- (2, 4]
- (4, 6]
- (6, 8]
- cot−1√2
- tan−1√3
- sec−1√3
- tan−1√2
The centroid if the , where and is
- y+4=0
- x−4=0
- y−4=0
- x+4=0
Prove that the line y - x + 2 = 0 divides the join of points (3, -1) and (8, 9) in the ratio 2 : 3.
- x+a=0
- x−2a=0
- y2−4x+6=0
- y2+4x−6=0
- y2=16x
- y2−16x+48=0
- y2−16x−48=0
- y2−4x+16=0
- 12
- 32
- 43
- 13
- both the tangents will always be perpendicular to each other
- extremities of the focal chord and intersection point of the tangents will lie on the circles discribed on the focal chord as diameter
- both the tangents need not be perpendicular to each other
- tangents will intersect each other at directrix
- x(t3+t1)(t21t23−1)+2yt1t3(t1t3+1)=0
- x(t3+t1)(t21t23+1)=2yt1t3(t1t3+1)
- x(t3−t1)(t21t23+1)=2yt1t3(t1t3+1)
- x(t3−t1)(t21t23+1)+2yt1t3(t1t3+1)=0
- ab+cd√(a2+b2)(c2+d2)
- ac+bd√(a2+b2)(c2+d2)
- ab+bd√(a2+b2)(c2+d2)
- None of these
- x2+y2−8x+12=0
- x2+y2+8x+12=0
- x2+y2−8x+9=0
- x2+y2=4
- y2=16x
- y2−16x+48=0
- y2−16x−48=0
- y2−4x+16=0
- t1t2=−4
- t1+t2=0
- 2t1+t2=0
- t1+2t2=0