Equation of a Line Passing through 2 Points
Trending Questions
4x+λy+2z=0
2x−y+z=0
μ+2y+3z=0, λ, μ∈R
has a non-trivial solution. Then which of the following is true?
- μ=6, λ∈R
- λ=2, μ∈R
- λ=3, μ∈R
- μ=−6, λ∈R
Let be a plane containing the line and parallel to the line If the point lies on the plane then the value of is equal to
x+y−z=2, x+2y+αz=1, 2x−y+z=β. If the system has infinite solutions, then α+β is equal to
Find the equation of the line joining (3, 1) and (9, 3) using determinants.
Which of the following lines is concurrent with the lines and ?
None of these
If the coordinates of the vertices of an equilateral triangle with sides of length 'a' are (x1, y1), (x2, y2) and (x3, y3), then
∣∣
∣∣x1y11x2y21x3y31∣∣
∣∣2=3a44
- any value of k
- k=−12 only
- integral values of k only
- no value of k
If the area of the triangle on the complex plane formed by the points is sq. units then the value of equals to:
Find the equation of the planes that passes through the sets of three points.
(1, 1, 0), (1, 2, 1), (-2, 2, -1)
- 1c−1d=1a−1b
- 1c+1d=1a+1b
- 1c−1b=1a−1d
- 1d−1c=1a−1b
x+3y+5z=αx
5x+y+3z=αy
3x+5y+z=αz
has infinite number of solutions is
- 1
- 3
- 9
- 15
If , then the value of and is
ax2x3+by2y3+cz2z3=ax3x1+by3y1+cz3z1=ax1x2+by1y2+cz1z2=f, where a, b, c, d, f>0 and d>2f, then the value of ∣∣ ∣∣x1y1z1x2y2z2x3y3z3∣∣ ∣∣ is:
- (d−f){(d+2f)abc}12
- |f−d|{(d−2f)abc}12
- (d−f){(d−2f)abc}12
- (d−f){(d+f)abc}12
Solve the equation. .
2x+y=3 and 4x+2y=5 is consistent.
- True
- False
- λ=5, γ=6
- λ=7, γ=5
- λ=γ
- λ=7, γ=6
Let X=1, 2, 3 and Y=4, 5. Find whether the following subsets of X×Y are functions from X to Y or not.
(i) f={(1, 4), (1, 5), (2, 4), (3, 5)}
(ii)g={(1, 4), (2, 4), (3, 4)}
(iii) h={(1, 4), (2, 5), (3, 5)}
(iv) k={(1, 4), (2, 5)}
2x1−4x2+λx3=1
x1−6x2+x3=2
λx1−10x2+4x3=3
is inconsistent for:
- exactly two values of λ.
- exactly one negative value of λ.
- every value of λ.
- exactly one positive value of λ.
x+y+z=22x+4y−z=63x+2y+λz=μ
has infinitely many solutions, then
- λ−2μ=−5
- 2λ+μ=14
- λ+2μ=14
- 2λ−μ=5
A straight line given by the equation ∣∣ ∣∣x+3y−117−11−391∣∣ ∣∣=0 passes through the point.
(4, -1)
(4, 0)
(6, 10)
(-6, 0)
- divisible by both x and y
- divisible by x but not y
- divisible by y but not x.
- divisible by neither x nor y.
pp−1+qq−1+rr−1=
- −1
- −2
- 2
- 1
- 8
- 9
- 16
- 44
The value of ∣∣ ∣∣a−bb+cab−ac+abc−aa+bc∣∣ ∣∣
(a) a3+b3+c3
(b) 3bc
(c) a3+b3+c3−3abc
(d) None of these
x+3y+5z=αx
5x+y+3z=αy
3x+5y+z=αz
has infinite number of solutions is
- 1
- 3
- 9
- 15