Equation of a Plane Passing through Three Points
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If four points P (1, 2, 3) , Q (2, 3, 4), R(3, 4, 5), S(4, 5, k) are coplanar then the value of k is / are -
6
4
5
Any real number.
Find the equation of plane passing through the points P (1, 1, 1) , Q (3, -1, 2) and R (-3, 5 , -4).
6x + 16y +16z - 44 = 0
x - 2y +16z - 13 = 0
6x + 6y +16z - 28 = 0
x + 6y +6z - 22 = 0
If a plane cuts off intercepts -6, 3, 4 from the co-ordinate axes, then the length of the perpendicular from the origin to the plane is
1√61
13√61
12√29
5√41
Let P be the image of the point (3, 1, 7) with respect to the plane x - y + z = 3. Then, the equation of the plane passing through P and containing the straight line x1=y2=z1 is
x + y - 3z = 0
3x + z = 0
x - 4y + 7z = 0
2x - y = 0
- 1
- 0
- no such k exists
- 7
If four points P (1, 2, 3) , Q (2, 3, 4), R(3, 4, 5), S(4, 5, k) are coplanar then the value of k is / are -
6
4
5
Any real number.
- 1x2+1y2+1z2=16p2
- 1x2+1y2+1z2=16p2
- 1x2+1y2+1z2=1p2
- 1x2+1y2+1z2=4p2
If a plane cuts off intercepts -6, 3, 4 from the co-ordinate axes, then the length of the perpendicular from the origin to the plane is