Family of Straight Lines
Trending Questions
- True
- False
A triangle with vertices (4, 0), (-1, -1), (3, 5) is
Isosceles but not right angled
Right angled but not isosceles
Neither right angled nor isosceles
Isosceles and right angled
Find the equation of straight line which passes through the point (2, -3) and the point of intersection of the lines x+y +4 = 0 and 3x-y-8=0
x-2y-7 = 0
2x-y-7 = 0
x-2y+7 = 0
2x-y+7 = 0
The corner points of the feasible region determined by the following system of linear inequalities :
2x+y≥10, x+3y≥15, x, y≥0 are(0, 0), (5, 0), (3, 4) and (0, 5). Let Z = px + qy, where p, q > 0. Condition on p and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is
(a) p = q
(b) p = 2q
(c) p = 3q
(d) q = 3p
How do you find slope with two variables?
straight line xsinα−ycosα=0 in the same point, then the value of a2+b2 is equal to
- 1
- 2
- 3
- 4
- 4x+3y+8=0
- 5x+3y+10=0
- 15x+8y+30=0
- 4x−3y+8=0
- 33x+12y−7=0
- 33x+12y+7=0
- 12x+33y+7=0
- 12x+33y−7=0
- (1, ∞)
- (0, ∞)
- (−1, ∞)
- (−1, 1)
The equation of the line which cuts off the intercepts and on the axes is
A line makes zero intercepts on x-axis and y-axis and it is perpendicular to another line The equation of line is
The equation of the normal to the curve at is
- 6x+15y+7=0
- 6x−15y+7=0
- 6x+15y+5=0
- 6x−15y+5=0
(x+y−1)+λ1(2x+3y−2)=0 and
(x−y+2)+λ2(2x−3y+5)=0
where λ1 and λ2∈R and one of the vertex of rhombus is (3, 2). If area of the rhombus is 12√5 square units, then the length of the longer diagonal of the rhombus is
- x+1=0
- x+y−1=0
- x−y+3=0
- x−y−3=0
(ax2+by2+c)(x2−5xy+6y2)=0 represents
- Four straight lines, when c=0 and a, b are of the same sign
- Two straight lines and a circle, when a=b and c is of sign opposite to that of a
- Two straight lines and a hyperbola, when a and b are of the same sign and c is of sign opposite to that of a
- A circle and an ellipse, when a and b are of the same sign and c is of sign opposite to that of a
- (1−√132, −1)∪(1, −1+√132)
- (−√3, √3)
- (1−√132, −1+√132)
- [−1, 1]
- True
- False
- 3x+4y+24=0
- 4x+3y−24=0
- 3x+4y−24=0
- 4x+3y+24=0
- (1, −1)
- (−1, 1)
- (1, 1)
- (−1, −1)
- 7x+3y=0
- 7x−y=0
- 3x+2y=0
- 3x+y=0
If a+b+c=0, then the family of lines 3ax+by+2c=0 pass through fixed point
(2, 23)
(23, 2)
(−2, 23)
none of these
- 4x−5y+5=0
- 4x+5y−5=0
- 4x−5y−5=0
- 4x+5y+5=0
Prove that the family of lines represented by x(1+λ)+y(2−λ)+5=0, λ being arbitary, pass through a fixed point .Also, find the fixed point.
- 112
- −112
- −12
- 12
- 7x+3y=0
- 7x−y=0
- 3x+2y=0
- 3x+y=0